F(0)+F(2)+...+F(2n) = F(2n+1) - 1
Wladimir Araujo Tavares
*Federal University of Ceará http://lia.ufc.br/%7Ewladimir/
Homepage http://lia.ufc.br/%7Ewladimir/ |
Maratonahttps://sites.google.com/site/quixadamaratona/|
*
On Sat, Oct 1, 2011 at 1:40 PM, rahul sharma rahul23111...@gmail.comwrote:
PLZ EXPLAIN A BIT MORE
On Sat, Oct 1, 2011 at 10:46 PM, Wladimir Tavares wladimir...@gmail.comwrote:
F(0)+F(2)+...+F(2n) = F(2n+1) - 1
Wladimir Araujo Tavares
*Federal University of Ceará http://lia.ufc.br/%7Ewladimir/
Homepage http://lia.ufc.br/%7Ewladimir/ |
I am I not wrong, the problem asks for fib numbers which are even, not fib
numbers with even index...?
On Sat, Oct 1, 2011 at 10:16 PM, Wladimir Tavares wladimir...@gmail.comwrote:
F(0)+F(2)+...+F(2n) = F(2n+1) - 1
Wladimir Araujo Tavares
*Federal University of Ceará
yeah like0 1 1 3 5 8 .only even shpuld be added 0+8..u r ryt
On Sat, Oct 1, 2011 at 10:56 PM, Shuaib Khan aries.shu...@gmail.com wrote:
I am I not wrong, the problem asks for fib numbers which are even, not fib
numbers with even index...?
On Sat, Oct 1, 2011 at 10:16 PM,
Sorry!
you want to find the following sum:
F (0) + F (3) + F (6) + ... + F (3n) =?
I do not know any formula for this sum.
This formula may help here:
F (0) + F (1) + F (2) + F (3 )+...+ F (n) = F (n +2) - 1
F (3n) = 3F (n) ^ 3 + 3 (-1) ^ nF (n)
You can prove this by induction!
Wladimir
check dis out
int fibbevensum()
{
static int a=0,b=1;
static int c,sum;
c=a+b;
if(c1000)
return sum;
if(c%2==0)
sum=sum+c;
a=b;
b=c;
fibbevensum();}
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its giving 16384???
On Sat, Oct 1, 2011 at 11:29 PM, geeks ankurshukla.h...@gmail.com wrote:
check dis out
int fibbevensum()
{
static int a=0,b=1;
static int c,sum;
c=a+b;
if(c1000)
return sum;
if(c%2==0)
sum=sum+c;
a=b;
b=c;
fibbevensum();}
--
You received this message because
it looks ok but not working
On Sat, Oct 1, 2011 at 11:37 PM, rahul sharma rahul23111...@gmail.comwrote:
its giving 16384???
On Sat, Oct 1, 2011 at 11:29 PM, geeks ankurshukla.h...@gmail.com wrote:
check dis out
int fibbevensum()
{
static int a=0,b=1;
static int c,sum;
c=a+b;
if(c1000)
@rahul:
here is the full working codE:
#includestdio.h
int fibbevensum()
{
static int a=0,b=1;
static int c=0,sum=0;
// printf(\nHi %d %d %d\n,a,b,sum);
c=a+b;
if(c8)
return sum;
if(c%2==0)
sum=sum+c;
a=b;
b=c;
int d=fibbevensum();
return d;}
int main(){
int ans;
