Hi,
Thanks Mr Romain Guy, for the information.
@Mike dg : The requirement is that one app has to be loaded at startup which
displays a browser with a specified URL. And one of the requirement is that
whatever buttons the user presses or clicks, the browser shouldn't exit. The
browser with the
So you're trying to be an iPhone? :D Yah, as they said, there is no way to
make that work.
Romain, one question on the Home key.. is there any way to detect it so you
can close your app when they press the Home key? I would assume the standard
lifecycle events still fire, so you can at least
That won't work. What you want to do is not possible unless you create
your own ActivityManager allowing just one activity: your activity. I
guess you have to create your own AOSP branch for this to happen.
All apps play by the same rules.
And what if the user gets a phone call?
What if a SMS
Quick question guys. I have no real knowledge in this but am quite
interested.
Assuming that the devices belong to an enterprise, can you just
replace the Home application with your application? Like...
http://developer.android.com/resources/samples/Home/index.html
That way when the home button
The dock app for the Droid does a similar thing. When you press the
home key (while in the dock) the dock app is displayed. In order to
get to the device home screen, the back key has to be pressed.
-John Coryat
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What are you trying to do? You could see that tons of things could go
wrong with an app that runs on boot and doesn't allow you to get away.
-Mike dg
On May 6, 3:07 am, Ashok Jeevan ashokjee...@gmail.com wrote:
Hi guys,
I am building an app which uses a WebView. This app runs at startup.
Is
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