Re: [android-kernel] Re: Flashing Android Kernel -- do I need to compile the entire source tree?

2012-09-05 Thread Ken Chen
> me to copy that to /device/samsung/tuna/kernel and then to make the entire >> project. >> >> Do I have to make the entire project if I just want the updated kernel? I >> also don't have the proprietary binaries -- since its sprint. >> >> Help would be mu

Re: [android-kernel] LXC support in android

2012-09-05 Thread Ken Chen
s > applications. > It can also be used to create sandbox and improve the security level for > android platform. > > -- > unsubscribe: android-kernel+unsubscr...@googlegroups.com > website: http://groups.google.com/group/android-kernel -- -- Ken Chen --

Re: [android-kernel] Configuring cgroups

2012-05-31 Thread Ken Chen
gt; my process? if not granting it. (in the kernel space as well as inside the > app) > You can not changing app_xx to root, but root can grant CAP_SYS_NICE to app_xx. > > > On Tue, May 29, 2012 at 4:17 PM, Ken Chen wrote: > >> Currently, Android dalvik VM leverages cpu

Re: [android-kernel] Configuring cgroups

2012-05-29 Thread Ken Chen
NER=y >> >> Why is mount saying device busy? >> >> note: I was following the steps in the documentation(sched-design- >> CFS.txt) >> >> Regards, >> Kanishka >> >> -- >> unsubscribe: android-kernel+unsubscr...@googlegroups.com &g

[android-kernel] Re: How to use shell command "rild"?

2009-04-24 Thread Ken, Chen
rild: command from application layer. Best regards bluebolt On 4月10日, 上午10時02分, "Ken, Chen" wrote: > I want to test reference-ril.c function on my test board. > One way is command from application layer. > Is there any way more direct on console mode? > > Thank

[android-kernel] Re: How to use shell command "rild"?

2009-04-09 Thread Ken, Chen
I want to test reference-ril.c function on my test board. One way is command from application layer. Is there any way more direct on console mode? Thanks for your answer. I totally misunderstood it. Best regards, bluebolt On Apr 9, 5:53 am, Mike Chan wrote: > Rild is a daemon, not a command,