Re: [Apertium-stuff] compounding

2012-11-07 Thread Francis Tyers
El dc 07 de 11 de 2012 a les 08:19 +0100, en/na Per Tunedal va escriure: Hi, it would be interesting to test compounded words. How do I proceed? I'm training on the pair Swedish (se) - Danish (da) before attacking Norwegian (no) - Swedish (se). Compounded words are very frequent in the

Re: [Apertium-stuff] compounding

2012-11-07 Thread keld
Hi Per just a littke comment: Swedish is sv, not se. We use ISO 639 language codes. It is correct that the ISO 3166 country code for Sweden is SE, but that is not for the language. For example in Finland they also speak some Swedish, and still the language code is sv for this. Best regards

Re: [Apertium-stuff] compounding

2012-11-07 Thread Per Tunedal
Oops! I did it again. I know this perfectly well, but just the same I have done the same error twice recently ... Shame on me! Yours, Per Tunedal On Wed, Nov 7, 2012, at 13:23, k...@keldix.com wrote: Hi Per just a littke comment: Swedish is sv, not se. We use ISO 639 language codes. It

Re: [Apertium-stuff] compounding

2012-11-07 Thread Per Tunedal
Hi, thank you. I've read the Wiki and looked into the apertium-nn-nb.nb.dix file. Apparently, this is solved in a less transparent way in the nn-nb pair than in the examples in the Wiki. In the beginning of the dictionary, there are a lot of pardefs treating compounds, that I don't understand.

Re: [Apertium-stuff] compounding

2012-11-07 Thread Francis Tyers
El dc 07 de 11 de 2012 a les 17:32 +0100, en/na Per Tunedal va escriure: Hi, thank you. I've read the Wiki and looked into the apertium-nn-nb.nb.dix file. Apparently, this is solved in a less transparent way in the nn-nb pair than in the examples in the Wiki. It's less transparent because

Re: [Apertium-stuff] compounding

2012-11-07 Thread Kevin Brubeck Unhammer
Francis Tyers fty...@prompsit.com writes: El dc 07 de 11 de 2012 a les 17:32 +0100, en/na Per Tunedal va escriure: Hi, thank you. I've read the Wiki and looked into the apertium-nn-nb.nb.dix file. Apparently, this is solved in a less transparent way in the nn-nb pair than in the examples