QUESTION: What is the purpose of the line my $msg = shift;? I am
guessing it is for the @_ array but what list element is there to be
shifted off? It seems that the shift function is in a lot of
subroutines and I am confused as to their purpose.
#!/bin/perl -w
(my $PROGNAME = $0) =~ s/^.*\///;
-Original Message-
From: Dave Adams [mailto:[EMAIL PROTECTED]
Sent: Tuesday, September 27, 2005 5:17 PM
To: beginners perl
Subject: Shift Question
QUESTION: What is the purpose of the line my $msg = shift;? I am
guessing it is for the @_ array but what list element
-Original Message-
From: Ryan Frantz
Sent: Tuesday, September 27, 2005 5:27 PM
To: Dave Adams; beginners perl
Subject: RE: Shift Question
-Original Message-
From: Dave Adams [mailto:[EMAIL PROTECTED]
Sent: Tuesday, September 27, 2005 5:17 PM
To: beginners perl
If I understood you question properly you want to know why people use
shift in subrutines and how does shift work.
I will try to make it short:
shift works on lists, it removes the first element of the list ( the 0
indexed element ) and returns it as a lvalue ( if there are no more
elements in a
Mulander wrote:
If I understood you question properly you want to know why people use
shift in subrutines and how does shift work.
I will try to make it short:
shift works on lists, it removes the first element of the list ( the 0
indexed element ) and returns it as a lvalue ( if there are
Mulander wrote:
If I understood you question properly you want to know why people use
shift in subrutines and how does shift work.
I will try to make it short:
shift works on lists, it removes the first element of the list
perldoc -q What is the difference between a list and an array
You
On Tue, 27 Sep 2005, Dave Adams wrote:
What is the purpose of the line my $msg = shift;?
In the context of subroutines, it copies the first scalar argument
passed to the routine to the variable $msg. If more than one argument
was passed, the others aren't touched by this statement -- as you
OK here comes the newbie question.
I found this in a template for creating subroutines, this is the base
that is created when you use the template to create the subroutine.
So now the newbie part, why would you place my $par1 = shift; in the
subroutine template, and what does it do??
Basically
[EMAIL PROTECTED] wrote:
OK here comes the newbie question.
I found this in a template for creating subroutines, this is the base
that is created when you use the template to create the subroutine.
So now the newbie part, why would you place my $par1 = shift; in
the subroutine template,
please
notify the sender immediately and delete the message.
-Original Message-
From: Bob Showalter [mailto:[EMAIL PROTECTED]
Sent: Monday, August 30, 2004 2:41 PM
To: Christopher L. Hood; [EMAIL PROTECTED]
Subject: RE: shift question
[EMAIL PROTECTED] wrote:
OK here comes the newbie
[EMAIL PROTECTED] wrote:
Ok fantastic, I totally understand that, and if there were going to be
more than one thing passed, just insert $par2 = shift; on the next
line and then the second argument is in $par2, I assume.right??
Yes.
You might also see it this way:
my ($par1, $par2) =
[EMAIL PROTECTED] wrote:
Ok fantastic, I totally understand that, and if there were going to be
more than one thing passed, just insert $par2 = shift; on the next
line and then the second argument is in $par2, I assume.right??
Yes.
You might also see it this way:
my ($par1,
Subject: RE: shift question
[EMAIL PROTECTED] wrote:
Ok fantastic, I totally understand that, and if there were going to be
more than one thing passed, just insert $par2 = shift; on the next
line and then the second argument is in $par2, I assume.right??
Yes.
You might also see
[EMAIL PROTECTED] wrote:
I found this in a template for creating subroutines, this is the base
that is created when you use the template to create the subroutine.
So now the newbie part, why would you place my $par1 = shift; in the
subroutine template, and what does it do??
Basically I am trying
Wim De Hul [EMAIL PROTECTED] writes:
my $var = shift;
I thought that shift puts a variable in an array? What does this mean?
Did you check the documentation on shift *before* posting
the question?
From Programming Perl:
3.2.143 shift
shift ARRAY
shift
This function
Hello guys ( and girls),
While I was reading a script, I saw the lines:
my $var = shift;
I thought that shift puts a variable in an array? What does this mean?
Thanks,
Wim.
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PROTECTED]]
Sent: 20 December 2001 15:48
To: [EMAIL PROTECTED]
Subject: Shift question...
Hello guys ( and girls),
While I was reading a script, I saw the lines:
my $var = shift;
I thought that shift puts a variable in an array? What does this mean?
Thanks,
Wim.
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To unsubscribe, e-mail: [EMAIL
[EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Subject: Shift question...
Date: Thu, 20 Dec 2001 16:48:16 +0100
Hello guys ( and girls),
While I was reading a script, I saw the lines:
my $var = shift;
I thought that shift puts a variable in an array? What does this mean?
Thanks,
Wim
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