Hello,
Could someone help point out how to use scalar within Xpath query? I need to
use $script in the query but it returns nothing.
I am somewhat confused about the interpolation in this case.
Thanks,
Isarin
use XML::XPath;
my $xp = XML::XPath-new(filename = '/dssweb/prog/navi/links.xml');
On Oct 14, H S said:
Could someone help point out how to use scalar within Xpath query? I need to
use $script in the query but it returns nothing.
I am somewhat confused about the interpolation in this case.
use XML::XPath;
my $xp = XML::XPath-new(filename = '/dssweb/prog/navi/links.xml');
Hi List,
I doing XML for the first path and got the things as
I wanted using XPath. However only one thing I cannot
figure out is how do I get Telephone number in a separate
list. What the module returning to me is concatenated list
of Telephone number and I have to add extra delimiter (space)
I gmane.comp.lang.perl.beginners, skrev Manish Sapariya:
my $doc = XML::XPath- new(xml=$xml);
my @agents = $doc- findnodes('//Agent');
foreach my $agent (@agents) {
print $agent- findvalue('TelephoneNumbers/TelephoneNumber'), \n;
}
This seems to work here:
