>Are you thinking of :
>
>( $a1,$b1,$a2,$b2,$a3,$b3,$a4,$b4,$a5,$b5 ) = $_ =~ /regexp/ ?
that might be what i need- if i'm going to be working with these values
alot, then i want to know what they are at the outset
>
>The result of a regexp ($1..$9) are returned in array context, so you
c
On Mon, 11 Oct 2004 13:13:37 -0600, Wiggins d Anconia
<[EMAIL PROTECTED]> wrote:
> > the following is an as yet incomplete regex that i'm working on:
> >
> > $data = $_ =~
> > s/<(name)>(.*?)<(desc)>(.*?)<(copy)>(.*?)<(license)>(.*?)<(entry)>//xg
> >
Are you thinking of :
( $a1,$b1,$a2,$b2,$a3,$
>-Original Message-
>From: Wiggins d Anconia [mailto:[EMAIL PROTECTED]
>Sent: Monday, October 11, 2004 3:14 PM
>To: West, William M; [EMAIL PROTECTED]
>Subject: Re: in a regex- re-arrange $1..$n
>
>> the following is an as yet incomplete regex that i&#
> the following is an as yet incomplete regex that i'm working on:
>
> $data = $_ =~
> s/<(name)>(.*?)<(desc)>(.*?)<(copy)>(.*?)<(license)>(.*?)<(entry)>//xg
>
>
> every other capture ($1 $3 $5 $7 $9) is going to be used one way, the
> other
> captures will be used differently... i'm wondering
the following is an as yet incomplete regex that i'm working on:
$data = $_ =~
s/<(name)>(.*?)<(desc)>(.*?)<(copy)>(.*?)<(license)>(.*?)<(entry)>//xg
every other capture ($1 $3 $5 $7 $9) is going to be used one way, the
other
captures will be used differently... i'm wondering if there's a way t
