Dear all,
There is another bug that sneaked into the speed patch of seq on 13.09.12:
560 if (all_digits_p (argv[optind])
561 (n_args == 1 || all_digits_p (argv[optind + 1]))
562 (n_args 3 || STREQ (1, argv[optind + 2]))
563 !equal_width !format_str strlen (separator)
On 01/22/2013 10:43 AM, Marcel Böhme wrote:
Dear all,
There is another bug that sneaked into the speed patch of seq on 13.09.12:
560 if (all_digits_p (argv[optind])
561(n_args == 1 || all_digits_p (argv[optind + 1]))
562(n_args 3 || STREQ (1, argv[optind + 2]))
563
On 01/22/2013 11:23 AM, Pádraig Brady wrote:
On 01/22/2013 10:43 AM, Marcel Böhme wrote:
Dear all,
There is another bug that sneaked into the speed patch of seq on 13.09.12:
560 if (all_digits_p (argv[optind])
561(n_args == 1 || all_digits_p (argv[optind + 1]))
562(n_args
On 01/22/2013 12:23 PM, Pádraig Brady wrote:
On 01/22/2013 10:43 AM, Marcel Böhme wrote:
Dear all,
There is another bug that sneaked into the speed patch of seq on 13.09.12:
560 if (all_digits_p (argv[optind])
561(n_args == 1 || all_digits_p (argv[optind + 1]))
562
On 01/22/2013 01:17 PM, Pádraig Brady wrote:
Updated patch attached.
That one is looking good ... but while we're at it:
Anyone tried this, i.e. a Zero as INCREMENT?
$ seq 1 0 2
This is equal to `yes 0`. Well, this is probably a (not
documented) feature, but in the following examples, the 1
On 01/22/2013 12:17 PM, Pádraig Brady wrote:
On 01/22/2013 11:23 AM, Pádraig Brady wrote:
On 01/22/2013 10:43 AM, Marcel Böhme wrote:
Dear all,
There is another bug that sneaked into the speed patch of seq on 13.09.12:
560 if (all_digits_p (argv[optind])
561(n_args == 1 ||
On 01/22/2013 12:28 PM, Bernhard Voelker wrote:
On 01/22/2013 01:17 PM, Pádraig Brady wrote:
Updated patch attached.
That one is looking good ... but while we're at it:
Anyone tried this, i.e. a Zero as INCREMENT?
$ seq 1 0 2
This is equal to `yes 0`. Well, this is probably a (not
On 01/22/2013 02:24 PM, Pádraig Brady wrote:
Yes I was wondering that myself.
Though I suppose that `seq 0 0 1` prints endlessly,
means that it's consistent that as long as start = end
and step == 0, then start is printed endlessly.
Yes, from a mathematical point of view, seq is right.
