Please see the makefile attached.
by running it it outputs:
VAR=foo VAR2=bar VAR3=foo
but I think VAR2 should be foo.
Bug or do I misunderstand something?
thanks,
Istvan
ifeq ($(VAR),foo)
VAR2=foo
else
VAR2=bar
endif
VAR3=$(VAR)
all:
make var1
make var2
var1: VAR=foo
You misunderstand something.
it outputs:
VAR=foo VAR2=bar VAR3=foo
That's only a small fraction of what I see, with make-3.81. This is what I see:
mart...@whitewater:~/tmp/bug-make-2009-05-07$ make
make var1
make[1]: Entering directory `/home/martind/tmp/bug-make-2009-05-07'
VAR=foo
Hi,
2009/5/7 Martin Dorey mdo...@bluearc.com:
That's only a small fraction of what I see, with make-3.81. This is what I
see:
[...]
VAR=foo VAR2=bar VAR3=foo
But here VAR2 should be foo As VAR=foo, the ifeq then-branch
should set it to foo, but it goes into the else branch - which I
But here VAR2 should be foo!
No, it shouldn't, for exactly the same reason that VAR2 isn't foo here:
mart...@whitewater:~/tmp/bug-make-2009-05-07$ make var1
VAR=foo VAR2=bar VAR3=foo
mart...@whitewater:~/tmp/bug-make-2009-05-07$
Despite the number of exclamation marks, it's not clear why you
VAR become foo when the var1 rule was executed.
it reevaluates because of the explicit make commands in the all rule.
Think about the order in which those two things happen.
The second one happens before the first and hence doesn't see the first's
effect.
A thought experiment might help you
(Re-adding list.)
First run
Second run
Make is run three times, once by the human, twice by the makefile. I'm not
sure what you mean with this numbering. I think you mean the first and second
runs of the echo command in the do-echo rule but please correct me if I'm wrong.
These can
2009/5/7 Martin Dorey mdo...@bluearc.com:
But here VAR2 should be foo!
No, it shouldn't, for exactly the same reason that VAR2 isn't foo here:
mart...@whitewater:~/tmp/bug-make-2009-05-07$ make var1
VAR=foo VAR2=bar VAR3=foo
mart...@whitewater:~/tmp/bug-make-2009-05-07$
Despite the number
