Right, so delocalizer's suggestion should work. You wouldn't even need
to do a find() first.
$this->Post->id = $var;
$this->Post->saveField('options', $value1);
$this->Post->updateAll(array('options'=>value2),array('id <>'=>'$var));
On Fri, Aug 21, 2009 at 8:18 AM, albe wrote:
>
> @ brian:
>
> W
@ brian:
What I need is to update existing records, and I've got to assign
$value2 as well as $value1... so I need the ELSE branch.
However, Thanks for the effort!
On 21 Ago, 13:56, brian wrote:
> Oops! I take that back. I just re-read the original post.
>
> On Fri, Aug 21, 2009 at 7:55 AM, bri
Oops! I take that back. I just re-read the original post.
On Fri, Aug 21, 2009 at 7:55 AM, brian wrote:
> I don't think albe is trying to update existing records, though. And,
> anyway, with your example, $value1 is never assigned.
>
> On Fri, Aug 21, 2009 at 7:17 AM, delocalizer
> wrote:
>>
>>
I don't think albe is trying to update existing records, though. And,
anyway, with your example, $value1 is never assigned.
On Fri, Aug 21, 2009 at 7:17 AM, delocalizer wrote:
>
> updateAll is the way to go...
> eg. $this->Post->updateAll(array('options'=>value2),array('id <>
> '=>'$var));
> redu
updateAll is the way to go...
eg. $this->Post->updateAll(array('options'=>value2),array('id <>
'=>'$var));
reducing the number of transactions in this case from n(Posts) to just
2 - one for the matching record and one for all the rest.
On Aug 21, 8:45 pm, brian wrote:
> Almost, but $value_2 will
Almost, but $value_2 will never be assigned. Perhaps the OP could shed
some light on the bigger picture as there may be a better way to
approach this.
On Fri, Aug 21, 2009 at 5:07 AM, rich...@home wrote:
>
> You don't need the else branch in the 2nd example, its taken care of
> in the read:
>
> /
You don't need the else branch in the 2nd example, its taken care of
in the read:
// fetch back the record with an id of $var
$post = $this->Post->read(null, $var);
// update the record
$post['Post']['options'] = value1;
// save the record
$this->Post->save($post);
In the first example, you fe
Please if anyone has an idea of the reason that could produce this
result let me know...
I've checked hundreds of times the code.
On 20 Ago, 16:26, AD7six wrote:
> On 20 ago, 15:39, albe wrote:
>
>
>
> > I have to make a foreach cycle to check every item of a certain group.
> > For each and eve
foreach($posts as $p) {
if ($p['Post']['id'] == $var) {
$p['Post']['options'] = value1;
} else {
$p['Post']['options'] = value 2;
}
$this->Post->save($p);
}
This works! I just can't say how much I am grateful for your help!
However I still don
Shouldn't that be:
foreach($posts as $p) {
if ($p['Post']['id'] == $var) {
$p['Post']['options'] = value1;
} else {
$p['Post']['options'] = value 2;
}
$this->Post->save($p);
}
also, if you are just matching against the id, you could just writ
On 20 ago, 15:39, albe wrote:
> I have to make a foreach cycle to check every item of a certain group.
> For each and every item I've got to check a condition and make a data
> modification depending on this condition.
> My code is the following:
>
> foreach($posts as $p) {
>
> $this->P
I have to make a foreach cycle to check every item of a certain group.
For each and every item I've got to check a condition and make a data
modification depending on this condition.
My code is the following:
foreach($posts as $p) {
$this->Post->id = $p['Post']['id']; //consider the post
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