There are still instances where rolling your own is the only good solution …
/thomas
> On 09 Sep 2014, at 03:51, #2Will wrote:
>
> Don't roll your own cms.
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really? for everything? how is it? do you ever find it's missing anything?
ecommerce, multi-language, plugins ?
nice looking new site for it, as my mum would say tho, needs more pictures.
On Tuesday, 9 September 2014 17:35:12 UTC+10, Marlin Cremers wrote:
>
> That's the reason why my company
That's the reason why my company uses Croogo. It gives us the ability to
have the ease of use of a CMS but with the raw power of CakePHP.
On Tuesday, 9 September 2014 06:08:22 UTC+2, Dakota wrote:
>
> Or use Croogo (croogo.com) and get the best of both worlds (cms and
> cakephp)
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Or use Croogo (croogo.com) and get the best of both worlds (cms and cakephp)
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You need a cms. have a look at silverstripe, statamic or wordpress.
depending on your needs, one of those will be lovely.
Don't use java. Don't roll your own cms.
have a great day
Will
On Tuesday, 2 September 2014 15:47:59 UTC+10, prakhil samar wrote:
>
> Hi All,
>
> Hope you all are doi
If all you need is a CMS I would suggest using an existing CMS rather than
trying to build one yourself in any language. There are many good CMS
packages available and some of them are based on CakePHP. CakePHP, or
another framework regardless of the language it is based on, is appropriate
for
Additional to what John said, in my experience hosting for Java
applications is usually more expensive than PHP applications, though it has
been a couple of years so this may no longer be the case...
On 2 September 2014 12:51, John Sposato wrote:
> When you say JAVA, I assume you mean a JAVA fr
When you say JAVA, I assume you mean a JAVA framework (Spring, Grails,
etc.) since I don't believe you can write a web application is straight
JAVA (I may be wrong). CakePHP is a framework, which follows the
Model/View/Controller pattern. The developers of the framework have
abstracted away a
Hi All,
Hope you all are doing well
I have a question, or i would say a confusion.
I need to built a website approx 80 web pages. This will be a CMS site.
I have a confusion that should i built that in JAVA or CakePHP.
Can someone please educate me exact differences between the both, i mean
Also, to use the $c variable in the view, you need to set it in the
controller:
$this->set('c', $this->M->getX());
http://book.cakephp.org/2.0/en/controllers.html#Controller::set
On Sunday, October 14, 2012 10:08:56 PM UTC-4, vinny M wrote:
>
> He's right seems like you made a mistake calling
He's right seems like you made a mistake calling your method with the wrong
name :)
VM
Sent from iPhone smartphone
On 2012-10-14, at 9:54 PM, sutikno sofjan wrote:
> controller M code
>
> class M_controller extends AppController{
>
> $this->M->setM(); << This is wrong. $this->M->s
controller M code
class M_controller extends AppController{
$this->M->setM(); << This is wrong. $this->M->setX();
$c = $this->M->getX();
}
On Mon, Oct 15, 2012 at 12:57 AM, Ashish Mahana wrote:
> if we declare a variable inside a model then we are unable to fetch its
> value in co
if we declare a variable inside a model then we are unable to fetch its
value in controller
e.g.
Model M code:
class M extends AppModel
{
var $x;
function setX(){
$this->x = "hello";
}
function getX(){
return $this->x;
}
}
controller M code
class M_controller extends AppController{
the default home.ctp has a display to inform if rewrite is not working.
is the cake.generic stylesheet applied & can you view localhost/pages/home
(with css applied too)?
if the answer to the above is yes then all is well the home.ctp you have is
displaying an element that the stylesheet should hid
hello,buddies.
i can visited the website in my computer using locahost with /posts/
index or /posts/view(is apache running the module of rewrite
successful ?the controllers and models are ok.),but cakephp show me
the errors:
URL rewriting is not properly configured on your server.
Help me configu
Hi
In my menu (jquery plugin named (mb)Menu) i wrote a simple login form:
Login panel
create('User', array('action' => 'login')); ?>
login:
input('username', array('label' => '')); ?>
password:
input('password', array('type' => 'password',
'label' => '')); ?>
end('Log in!'); ?
Thanks for the tip! :)
- Original Message
From: keymaster <[EMAIL PROTECTED]>
To: CakePHP
Sent: Thursday, May 22, 2008 10:01:19 AM
Subject: Re: Why CakePHP always uses var?
For symptomatic relief in Zend Studio:
- right click in the debug messages window,
- choose: Debug M
For symptomatic relief in Zend Studio:
- right click in the debug messages window,
- choose: Debug Message Filters
- unselect: Strict Messages.
On May 22, 8:19 am, José Lorenzo <[EMAIL PROTECTED]> wrote:
> > It's a real pain, because Zend Studio reports all the usages of var is
> > a compile w
var was undeprecated on 5.2
On May 22, 12:03 pm, mustan9 <[EMAIL PROTECTED]> wrote:
> Hi,
>
> The var keyword is deprecated in PHP5. The Cake documentation and
> source code constantly use this keyword to define properties for
> classes. The documentation should be changed, and all references to
That's a good compromise, IMO.
Thanks for the link. I haven't kept up on what's in store. This looks
particularly tasty:
// iterate over multi-dimensional array
foreach( $a as $k => list($b, $c))
(the example shown wouldn't work because $a was used twice)
On Wed, May 21, 2008 at 2:23 PM, Dardo
Anyway, isn't var coming again in PHP 6 ?
http://www.corephp.co.uk/archives/19-Prepare-for-PHP-6.html
On Wed, May 21, 2008 at 2:06 PM, Chris Hartjes <[EMAIL PROTECTED]> wrote:
>
> On Wed, May 21, 2008 at 1:03 PM, mustan9 <[EMAIL PROTECTED]> wrote:
>>
>> Hi,
>>
>> The var keyword is deprecated in
On Wed, May 21, 2008 at 1:03 PM, mustan9 <[EMAIL PROTECTED]> wrote:
>
> Hi,
>
> The var keyword is deprecated in PHP5. The Cake documentation and
> source code constantly use this keyword to define properties for
> classes. The documentation should be changed, and all references to
> var should be
> "The PHP 4 method of declaring a variable with the var keyword is
> still supported for compatibility reasons (as a synonym for the public
> keyword). In PHP 5 before 5.1.3, its usage would generate an E_STRICT
> warning."
CakePHP is designed to be compatible with PHP4 as well as PHP5. You'll
h
Hi,
The var keyword is deprecated in PHP5. The Cake documentation and
source code constantly use this keyword to define properties for
classes. The documentation should be changed, and all references to
var should be replaced with the correct visibility of that member
variable.
for example;
cla
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