Hey all,
I have (or plan to have!) an app that will allow users to view
products by category. Each category can have a sub category and each
sub category can have further sub categories..
eg. sportstennisracketswooden
There is no limit to the dept of sub categories.. (like in Ebay)
I plan to
Try Tree Behavior for category-SubCategory-SubCategory ,
and workit all in the same model Category ...
Product Model
public $hasAndBelongsToMany = array('Category');
Category Model
public $hasAndBelongsToMany = array('Product');
public $hasMany = array('SubCategory'=
Thats great thanks, looking at the cook book section on tree's and
although I dont quite get it at first glance, it looks like its
exactly what I need
Thanks again,
Kevin
On May 14, 10:49 am, PaulMan pho...@gmail.com wrote:
Try Tree Behavior for category-SubCategory-SubCategory ,
and workit
Now that I think about it, would a tree structure mean that each sub
category can only appear in one tree?
e.g a furniture shop might have
Living room tables
and
Dining Room tables
so can the sub category tables appear in both trees?
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No,
I Tree has unique branches..
A Table for Dining Room , is not a table for a Living Room but i
think if you reverse the order you will get more organized
put
Tables( id:5 ) - Living Room ( id:6 )
Tables( id:5 ) - Dinning Room ( id:7 )
* ids are only examples
and on the
On Thu, May 14, 2009 at 6:50 AM, PaulMan pho...@gmail.com wrote:
No,
I Tree has unique branches..
A Table for Dining Room , is not a table for a Living Room but i
think if you reverse the order you will get more organized
put
Tables( id:5 ) - Living Room ( id:6 )
Tables( id:5 ) -
You should analize you problem realy good,
I has a similar problem, on a Food Chain Distribution B2b Site and it
worked 5 Stars for me.
Good Luck...
On May 14, 4:28 pm, brian bally.z...@gmail.com wrote:
On Thu, May 14, 2009 at 6:50 AM, PaulMan pho...@gmail.com wrote:
No,
I Tree has
On Mar 1, 6:02 pm, Anthony [EMAIL PROTECTED] wrote:
OK, I'm aware this is probably a very dumb, newbie question, but you
gotta start somewhere, right?
Say I have a users table and a messages table. For each ONE user,
there are MULTIPLE messages. However, when doing a findAll on the
users,
Thanks, that solved the problem!!
- Anthony
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