Tim Dunphy writes:
> I'm very grateful. Ok so here is what I have so far of my script to get the
> number of apache requests to a given host:
> [...]
> So now my question is, is there any way to limit the size of the output log
> from within the script without having to use logrotate?
You could
On 6/3/2014 11:55 AM, Tim Dunphy wrote:
> Ok this is what I came up with:
>
> #!/bin/bash
> # this script parses mod_status to see which hosts are getting the most
> requests
>
> while true
> do
> echo "Time and date: $(/bin/date +"%D %H:%M:%S")" >>
> /tmp/apache_request_log >> /tmp/apache_request_
On Tue, Jun 03, 2014 at 11:55:55AM -0400, Tim Dunphy wrote:
> while true
> do
> echo "Time and date: $(/bin/date +"%D %H:%M:%S")" >>
> /tmp/apache_request_log >> /tmp/apache_request_log
> echo ???hostname: $(/bin/hostname -f)\n??? >> /tmp/apache_request_log
> echo ???host ip: $(/bin/hostname -i)?
Ok this is what I came up with:
#!/bin/bash
# this script parses mod_status to see which hosts are getting the most
requests
while true
do
echo "Time and date: $(/bin/date +"%D %H:%M:%S")" >>
/tmp/apache_request_log >> /tmp/apache_request_log
echo “hostname: $(/bin/hostname -f)\n” >> /tmp/apach
op 03-06-14 16:32, schreef Tim Dunphy:
What I need to figure out at this point is how to get the time and date
info on the same line as it's category. ie get
Time and date: 06/03/14 10:24:09
instead of
Time and date:
06/03/14 10:24:09
printf "Time and date: $(/bin/date +"%D %H:%M:%S")\n" sol
On 2014-06-03, Tim Dunphy wrote:
> Ok! So this is where my script is at this point:
I strongly suggest that if you are writing a program to use a better
language. bash is really painful for this sort of task. Here's a
Perl script that queries /server-status:
http://www.perlmonks.org/?node_id=4
Ok! So this is where my script is at this point:
#!/bin/bash
# this script parses mod_status to see which hosts are getting the most
requests
while true
do
echo "Time and date:" >> /tmp/apache_request_log
/bin/date +"%D %H:%M:%S" >> /tmp/apache_request_log
echo -e "\n"
echo “hostname:” >> /tmp/
>
> Try accessing the stats with the additional "?auto" suffix, it is meant to
> be machine-readable, and is much shorter, e.g:
>
> http://$(hostname -i)/server-status/?auto
Awesome tip! This is some of the output I get when I run this command:
[root@uszmpwslp014lc script]# GET $(hostname -f)/s
On Tue, Jun 3, 2014 at 4:56 PM, Tim Dunphy wrote:
> Guys,
>
> Thank you all for your input. I can't believe how helpful this list is and
> I'm very grateful. Ok so here is what I have so far of my script to get the
> number of apache requests to a given host:
>
> #!/bin/bash
>
> # this script pa
Guys,
Thank you all for your input. I can't believe how helpful this list is and
I'm very grateful. Ok so here is what I have so far of my script to get the
number of apache requests to a given host:
#!/bin/bash
# this script parses mod_status to see which hosts are getting the most
requests
op 03-06-14 15:18, schreef Tim Dunphy:
[root@uszmpwslp014lc ~]# GET http://$(hostname -i)/server-status | grep
-i requests/sec
4.08 requests/sec - 80.9 kB/second - 19.8 kB/request
That works ok. And next I'm grepping it back down and awking it to just the
part I'm interested in:
[root@usz
hey all,
I'm trying to figure out how to use apache's mod_status module to figure
out which of the web servers in a farm of six are processing more requests
than others.
I'm writing a script to grep out requests per second from the status
module like this:
[root@uszmpwslp014lc ~]# GET http://
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