Convert the length to decimal (0x11000 = 24, and 0x00110 = 6). Count the
number of bytes the RIF is (hint - each hex character is one byte, so there
are two bytes for the RC, and two more for each RD).
Since the first problem has a length of 24 bytes defined, but an actual
length of 8 bytes, it
first rif has a length of eight bytes but the length field says 24.
A correct RIF would be C820.0123.0321.0050. This is read as:
110 - single route broadcast (spanning explorer)
01000 - length of eight
0 - read left to right
010 - max length of 2052 byt
ECTED]]On Behalf Of
Dennis Laganiere
Sent: Saturday, March 16, 2002 7:58 PM
To: [EMAIL PROTECTED]
Subject: RE: Problem with RIF [7:38569]
Convert the length to decimal (0x11000 = 24, and 0x00110 = 6). Count the
number of bytes the RIF is (hint - each hex character is one byte, so there
are two byte
ct: RE: Problem with RIF [7:38569]
Convert the length to decimal (0x11000 = 24, and 0x00110 = 6). Count the
number of bytes the RIF is (hint - each hex character is one byte, so there
are two bytes for the RC, and two more for each RD).
Since the first problem has a length of 24 bytes defined
work Specialist / Adjunct Faculty
Computing & Engineering Technology
Manatee Community College
-Original Message-
From: Dennis Laganiere [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, March 20, 2002 1:43 AM
To: [EMAIL PROTECTED]
Subject: RE: Problem with RIF [7:38569]
I finally put up a web
5 matches
Mail list logo