Re: new access list problem [7:63715]

2003-02-25 Thread Priscilla Oppenheimer
Robert Edmonds wrote: > > Couldn't you just use the wildcard mask 0.0.4.255 to deny > 192.17.73.0 - > 192.17.77.0? I used the Boson wildcard mask calculator to > check this, and > it gave me those networks. If the mask is 0.0.4.255, it will deny 192.17.73.0 as well as 192.17.77.0. However, it wo

Re: new access list problem [7:63715]

2003-02-25 Thread Priscilla Oppenheimer
I replied too and it wasn't posted. That is SO annoying. I'm tempted to never post again. Anyway, your answer is wrong because it doesn't catch 74, 75, and 76, and he said he wanted a range. You have to use 0.0.7.255, which has an unfortunate (but unavoidable) side effect of catching 72, and 78 a

Re: new access list problem [7:63715]

2003-02-25 Thread Robert Edmonds
I replied earlier, but it didn't seem to come through. Anyway, you should use the wildcard mask 0.0.4.255. That will match the addresses 192.17.73.0 - 192.172.77.255, which I think is what you want. In case you don't already have it, download Boson's free wildcard mask calculator at the followin

Re: new access list problem [7:63715]

2003-02-25 Thread Robert Edmonds
Couldn't you just use the wildcard mask 0.0.4.255 to deny 192.17.73.0 - 192.17.77.0? I used the Boson wildcard mask calculator to check this, and it gave me those networks. ""Andrew Larkins"" wrote in message news:[EMAIL PROTECTED] > the first access-list will not work. > The second one will als

RE: new access list problem [7:63715]

2003-02-25 Thread Andrew Larkins
the first access-list will not work. The second one will also deny networks 192.17.72.0 and 78.0 as well as 79.0 - You are correct about zeros must make at 1's are don't care, but you need to understand the basic of subnetting. A 248.0 subnet mask means 8 "Class C" subnets. You have to start at a