Do not understand why loop takes 3 arguments who are all the same

Hello, Im now at the last exercise of the beginners exercise of 4clojure. I figured out that this solution works. (fn [default lijst1] (loop [lijst lijst1 d {}] (if (empty? lijst) d (recur (rest lijst) (assoc d (first lijst) default) But as I see it lijst lijst 1 and

Re: Do not understand why loop takes 3 arguments who are all the same

Hi Roelof, On May 3, 2014, at 3:09 AM, Roelof Wobben rwob...@hotmail.com wrote: Hello, Im now at the last exercise of the beginners exercise of 4clojure. nice! I figured out that this solution works. (fn [default lijst1] (loop [lijst lijst1 d {}] (if (empty? lijst)

Re: Do not understand why loop takes 3 arguments who are all the same

(fn [default initial-keys] (loop [remaining-keys initial-keys result-map {}] (if (empty? remaining-keys) result-map (let [key (first remaining-keys) remaining-keys' (rest remaining-keys) result-map' (assoc

Re: Do not understand why loop takes 3 arguments who are all the same

On May 3, 2014, at 6:42 AM, Roelof Wobben rwob...@hotmail.com wrote: (fn [default initial-keys] (loop [remaining-keys initial-keys result-map {}] (if (empty? remaining-keys) result-map (let [key (first remaining-keys)