System.out.println( new StringBuilder().toString() == "" );
-> "false"
Any reason for not returning the "" instance?
public String toString() {
return new String(value, 0, count);
}
-->
public String toString() {
return (count > 0) ? new String(value, 0, count) : "
Probably because the API-Spec
(http://docs.oracle.com/javase/7/docs/api/java/lang/StringBuilder.html#toString%28%29)
says "..A new String object is allocated and initialized to contain
the character sequence currently represented by this object..".
Regards,
Volker
On Thu, Feb 28, 2013 at 8:47 AM,
On 02/28/2013 09:07 AM, Volker Simonis wrote:
Probably because the API-Spec
(http://docs.oracle.com/javase/7/docs/api/java/lang/StringBuilder.html#toString%28%29)
says "..A new String object is allocated and initialized to contain
the character sequence currently represented by this object..".
R
Yes, makes sense to avoid the branching in that method.
Thanks.
On Thu, Feb 28, 2013 at 10:23 AM, Remi Forax wrote:
> On 02/28/2013 09:07 AM, Volker Simonis wrote:
>
>> Probably because the API-Spec
>> (http://docs.oracle.com/**javase/7/docs/api/java/lang/**
>> StringBuilder.html#toString%**28
