On 9/8/2013 6:03 AM, "Øivind" wrote:
That throws safety out the window for one. If you want safety and
no new language features, this should work:
a[base..$][0..width]
Thanks
Still a little verbose, but at least you don't have to type the same things
twice.
I guess the double slice will b
On Sunday, 8 September 2013 at 12:08:50 UTC, Simen Kjaeraas wrote:
On 2013-09-08, 14:02, Chang Long wrote:
On Sunday, 8 September 2013 at 10:53:23 UTC, Øivind wrote:
a[c -: d] //D: a[c-d .. c]
I think this should be
a[c -: d] //D: a[c-d+1 .. c+1], e.g. a[5 -: 2] == [a[4],
a[5]]
t
On 2013-09-08, 14:02, Chang Long wrote:
On Sunday, 8 September 2013 at 10:53:23 UTC, Øivind wrote:
a[c -: d] //D: a[c-d .. c]
I think this should be
a[c -: d] //D: a[c-d+1 .. c+1], e.g. a[5 -: 2] == [a[4], a[5]]
try &a[base][0..width]
That throws safety out the window for one. I
On Sunday, 8 September 2013 at 10:53:23 UTC, Øivind wrote:
a[c -: d] //D: a[c-d .. c]
I think this should be
a[c -: d] //D: a[c-d+1 .. c+1], e.g. a[5 -: 2] == [a[4],
a[5]]
try &a[base][0..width]
a[c -: d] //D: a[c-d .. c]
I think this should be
a[c -: d] //D: a[c-d+1 .. c+1], e.g. a[5 -: 2] == [a[4], a[5]]
I find myself writing the following a lot:
a[base..base+width]
to get the slice starting at 'base' of width 'width'. In verilog,
we select members of a vector/array in three ways
a[c : d] //D: a[c .. d+1]
a[c +: d] //D: a[c .. c+d]
a[c -: d] //D: a[c-d .. c]
Borrowing a bi
