On Friday, November 16, 2012 21:31:26 Rob T wrote:
> My understanding is that a struct will have a default postblit
> opAssign. What I want to know is if I can call the default
> opAssign after overriding it, or is it inaccessible?
>
> I know that I do not have to execute the default after
> overr
My understanding is that a struct will have a default postblit
opAssign. What I want to know is if I can call the default
opAssign after overriding it, or is it inaccessible?
I know that I do not have to execute the default after
overriding, but if I can call it, I'd like to know because in
s
Thanks a lot, it was very helpful.
On Friday, 16 November 2012 at 19:15:09 UTC, Sparsh Mittal wrote:
I want to call an external program (e.g. ls or date) in D.
This function should do for many tasks:
http://dlang.org/phobos/std_process.html#shell
string shell(string cmd);
Runs cmd in a shell and returns its standard outpu
On 2012-11-16, 17:37, bearophile wrote:
Simen Kjaeraas:
There. Now it works, and returns a Tuple!(ulong,ulong)(8, 8).
One thing I think is ugly in my implementation is acc + (seq == 'G').
This
adds a bool and a ulong together. For more points, replace that with
acc + (seq == 'G' ? 1 : 0).
Simen Kjaeraas:
There. Now it works, and returns a Tuple!(ulong,ulong)(8, 8).
One thing I think is ugly in my implementation is acc + (seq ==
'G'). This
adds a bool and a ulong together. For more points, replace that
with
acc + (seq == 'G' ? 1 : 0).
I use a pragmatic approach: I use such h
On 2012-11-16, 16:49, bioinfornatics wrote:
hi,
I would like to count number of one ore more letter into a string or
list of string (string[]) without use a for loop but instead using
std.algorithm to compute efficiently.
if you have:
string seq1 = "ACGATCGATCGATCGCGCTAGCTAGCTAG";
s
bioinfornatics:
I would like to count number of one ore more letter into a
string or list of string (string[]) without use a for loop but
instead using std.algorithm to compute efficiently.
If it's speed you look for, then most times std.algorithm is not
the solution. Basic loops are usually
hi,
I would like to count number of one ore more letter into a string
or list of string (string[]) without use a for loop but instead
using std.algorithm to compute efficiently.
if you have:
string seq1 = "ACGATCGATCGATCGCGCTAGCTAGCTAG";
string[] seq2 = ["ACGATCGATCGATCGCGCTAGCTAGCTAG",
On 11/16/2012 12:55 PM, Joseph Rushton Wakeling wrote:
The trouble is that it's not such a simple structure: it's actually more like,
I should add that I'm not trying to be coy about revealing my code; I'm happy to
do so, but as it's a rather long file I don't want to oblige anyone to have to
On 11/16/2012 05:51 AM, Ali Çehreli wrote:
However, if makeFoo() does not care, then it would be better if it returned a
mutable Foo:
Foo makeFoo() pure
In that case the callers could decide whether they wanted to have the returned
object as mutable or immutable:
immutable ifoo = makeFoo(
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