Charles Hixson:
Is this the way things are supposed to happen? (Changing the
struct to a class is an OK patch, but I don't understand why it
should either work or be necessary.)
Please show a complete very little program, and maybe someone
will try to help you.
(Eventually it's a good
Please show a complete very little program, and maybe someone
will try to help you.
I've seen there is code in another (broken) thread, so please
ignore this request.
Bye,
bearophile
I have an interface that I would like to make sure that any
classes derived from it will use alias this, else it can
potentially break code.
interface A(T)
{
@property T Value();
@property T Value(T value);
// need to enforce alias _value this somehow
}
class B(T) : A!T
{
Simen Kjaeraas:
However, you can amend std.traits.EnumMembers to work
with larger enums by using this version:
Worth putting in Phobos?
Bye,
bearophile
interface A(T)
{
@property T Value();
@property T Value(T value);
// need to enforce alias Value this somehow
}
class B(T) : A!T
{
private T _value;
@property T Value() { return _value; }
@property T Value(T value) { return value = _value; }
alias Value this;
this may seem a bit nonsensical but it is just an example:
interface A(T, S...)
{
... Generate a getter for each type in S...
// e.g., @property S[0] property1();
// @property S[1] property2();
//
}
I imagine I have to use a mixin template but I'm unsure how to
create a
On Monday, 8 July 2013 at 08:59:16 UTC, JS wrote:
I have an interface that I would like to make sure that any
classes derived from it will use alias this, else it can
potentially break code.
interface A(T)
{
@property T Value();
@property T Value(T value);
// need to enforce alias
On Monday, 8 July 2013 at 09:52:44 UTC, John Colvin wrote:
Most other solutions I tried failed because the compiler
evaluates the check (e.g. out contracts) in the interface,
which makes the check either semantically wrong, or statically
false/failed.
Woops, should be the contract exists in
On Monday, 8 July 2013 at 09:34:46 UTC, JS wrote:
this may seem a bit nonsensical but it is just an example:
interface A(T, S...)
{
... Generate a getter for each type in S...
// e.g., @property S[0] property1();
// @property S[1] property2();
//
}
I imagine I have to
On Monday, 8 July 2013 at 09:03:24 UTC, bearophile wrote:
Simen Kjaeraas:
However, you can amend std.traits.EnumMembers to work
with larger enums by using this version:
Worth putting in Phobos?
Bye,
bearophile
I reckon so. It's rare to have such huge structs or classes that
this sort of
On Monday, 8 July 2013 at 10:16:22 UTC, John Colvin wrote:
On Monday, 8 July 2013 at 09:34:46 UTC, JS wrote:
this may seem a bit nonsensical but it is just an example:
interface A(T, S...)
{
... Generate a getter for each type in S...
// e.g., @property S[0] property1();
//
On Monday, 8 July 2013 at 09:55:29 UTC, John Colvin wrote:
On Monday, 8 July 2013 at 09:52:44 UTC, John Colvin wrote:
Most other solutions I tried failed because the compiler
evaluates the check (e.g. out contracts) in the interface,
which makes the check either semantically wrong, or
On 2013-07-08, 11:03, bearophile wrote:
Simen Kjaeraas:
However, you can amend std.traits.EnumMembers to work
with larger enums by using this version:
Worth putting in Phobos?
Filed:
http://d.puremagic.com/issues/show_bug.cgi?id=10569
And created a pull request:
On 07/08/13 13:25, JS wrote:
mixin template a(T...)
{
template b(TT...)
{
static string eval()
{
string s;
int i = 0;
foreach(t; TT)
s = @property ~(t).stringof~ Name~to!string(i++)~();\n;
return s;
On Monday, 8 July 2013 at 13:01:32 UTC, Artur Skawina wrote:
It won't work if one of the types isn't already available
inside the
template - the .stringof will give you the name, but the mixin
will fail;
When would the type not be available?
On Monday, 8 July 2013 at 11:37:31 UTC, JS wrote:
On Monday, 8 July 2013 at 09:55:29 UTC, John Colvin wrote:
On Monday, 8 July 2013 at 09:52:44 UTC, John Colvin wrote:
Most other solutions I tried failed because the compiler
evaluates the check (e.g. out contracts) in the interface,
which
On 07/08/13 15:12, John Colvin wrote:
On Monday, 8 July 2013 at 13:01:32 UTC, Artur Skawina wrote:
It won't work if one of the types isn't already available inside the
template - the .stringof will give you the name, but the mixin
will fail;
When would the type not be available?
auto
On Monday, 8 July 2013 at 13:42:36 UTC, Artur Skawina wrote:
On 07/08/13 15:12, John Colvin wrote:
On Monday, 8 July 2013 at 13:01:32 UTC, Artur Skawina wrote:
It won't work if one of the types isn't already available
inside the
template - the .stringof will give you the name, but the mixin
On 07/08/13 16:12, John Colvin wrote:
On Monday, 8 July 2013 at 13:42:36 UTC, Artur Skawina wrote:
On 07/08/13 15:12, John Colvin wrote:
On Monday, 8 July 2013 at 13:01:32 UTC, Artur Skawina wrote:
It won't work if one of the types isn't already available inside the
template - the .stringof
On Monday, 8 July 2013 at 14:25:17 UTC, Artur Skawina wrote:
On 07/08/13 16:12, John Colvin wrote:
On Monday, 8 July 2013 at 13:42:36 UTC, Artur Skawina wrote:
On 07/08/13 15:12, John Colvin wrote:
On Monday, 8 July 2013 at 13:01:32 UTC, Artur Skawina wrote:
It won't work if one of the types
Am Thu, 04 Jul 2013 15:54:48 +0200
schrieb monarch_dodra monarchdo...@gmail.com:
This should work:
int[] *pSlice = (new int[][1]).ptr;
-Steve
Hum... That would allocate a dynamic array of slices though
right? There'd be the Appendable overhead for just one element...
No, it
On Monday, 8 July 2013 at 15:43:21 UTC, Marco Leise wrote:
Am Thu, 04 Jul 2013 15:54:48 +0200
schrieb monarch_dodra monarchdo...@gmail.com:
This should work:
int[] *pSlice = (new int[][1]).ptr;
-Steve
Hum... That would allocate a dynamic array of slices though
right? There'd be the
Am Mon, 08 Jul 2013 10:59:14 +0200
schrieb JS js.m...@gmail.com:
I have an interface that I would like to make sure that any
classes derived from it will use alias this, else it can
potentially break code.
interface A(T)
{
@property T Value();
@property T Value(T value);
On Monday, 8 July 2013 at 03:35:03 UTC, Jesse Phillips wrote:
On Monday, 8 July 2013 at 02:42:50 UTC, JohnnyK wrote:
Hi all,
I have searched everywhere over the Internet and I have yet
to find a way to clone a project using git when my workstation
is behind a company proxy. Can you guys
On Monday, 8 July 2013 at 02:42:50 UTC, JohnnyK wrote:
Hi all,
I have searched everywhere over the Internet and I have yet
to find a way to clone a project using git when my workstation
is behind a company proxy. Can you guys clone your projects to
a single zip file that I can download?
On Monday, 8 July 2013 at 16:24:53 UTC, JohnnyK wrote:
On Monday, 8 July 2013 at 03:35:03 UTC, Jesse Phillips wrote:
On Monday, 8 July 2013 at 02:42:50 UTC, JohnnyK wrote:
Hi all,
I have searched everywhere over the Internet and I have yet
to find a way to clone a project using git when my
Yeah, not very exiting, but I just spent an hour tracking down
the fix, but now I'd like to track down *what* was making it
break (my fix was luck). This should help Kenji (or others)
have an easier time fixing it :)
Also, I'm only repro'ing this on linux...
I think there are two things
On Monday, 8 July 2013 at 16:49:05 UTC, John Colvin wrote:
On Monday, 8 July 2013 at 16:24:53 UTC, JohnnyK wrote:
On Monday, 8 July 2013 at 03:35:03 UTC, Jesse Phillips wrote:
On Monday, 8 July 2013 at 02:42:50 UTC, JohnnyK wrote:
Hi all,
I have searched everywhere over the Internet and I
On Monday, 8 July 2013 at 16:24:53 UTC, JohnnyK wrote:
It would be nice if GitHUB would change their Downlaod Zip
button such that it does a recursive zip to include all the
subfolders.
Ehhh, well that is useless. Sorry I couldn't hook you up with a
solution.
On 07/08/13 19:54, monarch_dodra wrote:
struct S(R)
{
R _input;
void foo()
{
static assert(is(typeof(_input[size_t.max .. size_t.max]))); //ok
static assert(is(typeof(_input[size_t.max .. $]))); //ok
}
static assert(is(typeof(_input[size_t.max ..
On Monday, 8 July 2013 at 18:09:44 UTC, monarch_dodra wrote:
On Monday, 8 July 2013 at 16:49:05 UTC, John Colvin wrote:
On Monday, 8 July 2013 at 16:24:53 UTC, JohnnyK wrote:
On Monday, 8 July 2013 at 03:35:03 UTC, Jesse Phillips wrote:
On Monday, 8 July 2013 at 02:42:50 UTC, JohnnyK wrote:
On Monday, 8 July 2013 at 18:34:33 UTC, Jesse Phillips wrote:
On Monday, 8 July 2013 at 16:24:53 UTC, JohnnyK wrote:
It would be nice if GitHUB would change their Downlaod Zip
button such that it does a recursive zip to include all the
subfolders.
Ehhh, well that is useless. Sorry I
On Monday, 8 July 2013 at 19:37:08 UTC, JohnnyK wrote:
Another thing about GitHub's Download Zip button and this process
as a whole. While the Download Zip button does allow you to
download the master folders with recursive directories I do find
it somewhat cumbersome or should I say awkward
I'm trying to implement rational numbers with fully functioning
comparison operators, but I can't seem to figure out why I'm
getting this error and any help would be appreciated:
Error: cannot cast from object.Object to Rat
The code I have is as follows:
int opCmp( Object o ) {
Rat
On Monday, July 08, 2013 23:21:59 Ugbar Ikenaki wrote:
I'm trying to implement rational numbers with fully functioning
comparison operators, but I can't seem to figure out why I'm
getting this error and any help would be appreciated:
Error: cannot cast from object.Object to Rat
The code I
Also…Rat is a struct, not a class. Herein might lie the problem.
Thanks for the quick response!
Here is the initialization code for my Rat struct. I created a
GCD function that I've tested to work fine:
import std.stdio, std.exception;
struct Rat {
private long n; //Numerator
private long d; //Denominator
On Monday, July 08, 2013 23:31:14 Ugbar Ikenaki wrote:
Also…Rat is a struct, not a class. Herein might lie the problem.
So, this is Rat's opCmp, correct? If it's a struct, it makes no sense for it
to take an Object. Object is the base class for all classes and has nothing to
do with structs.
On 07/08/2013 02:21 PM, Ugbar Ikenaki wrote:
I'm trying to implement rational numbers with fully functioning
comparison operators, but I can't seem to figure out why I'm getting
this error and any help would be appreciated:
Error: cannot cast from object.Object to Rat
The code I have is as
On Monday, 8 July 2013 at 18:55:30 UTC, Artur Skawina wrote:
On 07/08/13 19:54, monarch_dodra wrote:
struct S(R)
{
R _input;
void foo()
{
static assert(is(typeof(_input[size_t.max ..
size_t.max]))); //ok
static assert(is(typeof(_input[size_t.max .. $])));
//ok
On Mon, Jul 08, 2013 at 02:42:30PM -0700, Jonathan M Davis wrote:
On Monday, July 08, 2013 23:31:14 Ugbar Ikenaki wrote:
Also…Rat is a struct, not a class. Herein might lie the problem.
So, this is Rat's opCmp, correct? If it's a struct, it makes no sense
for it to take an Object. Object is
Wow! You guys are fast and helpful! Thank you Jonathan and Ali! I
already got it to work, and Ali, your book is great! I've read
about the first 150 pages. I'll check out those operator
overloading chapters for sure.
-U
And thanks for that pointer, too, H.S.
Here's one more question:
Before I knew that opEquals existed, I tried overloading the
equality expressions (== and !=) in opBinary using the code
below. It worked. Why would the overloaded opBinary version get
called if the equality expressions are held in opEquals? I'm just
interested in
On 07/08/13 23:45, monarch_dodra wrote:
On Monday, 8 July 2013 at 18:55:30 UTC, Artur Skawina wrote:
On 07/08/13 19:54, monarch_dodra wrote:
struct S(R)
{
R _input;
void foo()
{
static assert(is(typeof(_input[size_t.max .. size_t.max]))); //ok
static
On Tuesday, July 09, 2013 00:35:32 Ugbar Ikenaki wrote:
Here's one more question:
Before I knew that opEquals existed, I tried overloading the
equality expressions (== and !=) in opBinary using the code
below. It worked. Why would the overloaded opBinary version get
called if the equality
On Tue, Jul 09, 2013 at 12:35:32AM +0200, Ugbar Ikenaki wrote:
Here's one more question:
Before I knew that opEquals existed, I tried overloading the
equality expressions (== and !=) in opBinary using the code below.
It worked. Why would the overloaded opBinary version get called if
the
On Monday, July 08, 2013 16:38:16 H. S. Teoh wrote:
On Tue, Jul 09, 2013 at 12:35:32AM +0200, Ugbar Ikenaki wrote:
Here's one more question:
Before I knew that opEquals existed, I tried overloading the
equality expressions (== and !=) in opBinary using the code below.
It worked. Why
On Monday, July 08, 2013 16:48:05 Jonathan M Davis wrote:
On Monday, July 08, 2013 16:38:16 H. S. Teoh wrote:
On Tue, Jul 09, 2013 at 12:35:32AM +0200, Ugbar Ikenaki wrote:
Here's one more question:
Before I knew that opEquals existed, I tried overloading the
equality expressions
On Mon, Jul 08, 2013 at 04:48:05PM -0700, Jonathan M Davis wrote:
On Monday, July 08, 2013 16:38:16 H. S. Teoh wrote:
[...]
Basically, when you write x==y, the compiler looks for opEquals and
opCmp. If opEquals is found, then it's rewritten as x.opEquals(y);
otherwise, if opCmp is found,
On 07/09/13 00:43, Artur Skawina wrote:
On 07/08/13 23:45, monarch_dodra wrote:
But, the context pointer *should* be defined as whatever the owner of the
indexing/slicing object is, no? In this case, it's simply _input. It has
nothing to do with the this pointer being available...
If
On Monday, July 08, 2013 16:58:03 H. S. Teoh wrote:
On Mon, Jul 08, 2013 at 04:48:05PM -0700, Jonathan M Davis wrote:
On Monday, July 08, 2013 16:38:16 H. S. Teoh wrote:
[...]
Basically, when you write x==y, the compiler looks for opEquals and
opCmp. If opEquals is found, then it's
I'm a bit confused with the behavior of function type stringification:
int main(string[]args){
auto foo=main;
pragma(msg,typeid(typeof(foo)));
pragma(msg,typeid(typeof(foo)).stringof);
//pragma(msg,typeid(typeof(foo)));
import std.stdio;
writeln(typeid(typeof(foo)).stringof);
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