On Wednesday, 9 October 2013 at 04:41:35 UTC, Ali Çehreli wrote:
4. Data structures should not restrict themselves to be
mutable, const,
or immutable.
What is the template of a struct that can be used as such?
Providing simple values seems to be insufficient:
struct MyInt
{
int i;
Hi folks,
Is there anyway to make std.process.spawnShell or
std.process.pipeShell capture the output of the shell interface?
For example, the code:
import std.stdio;
import std.process;
void main(string[] args){
writefln(Executing: %s, args[1]);
auto processPipes =
i've found the solution:
void put(T)(T mesh) {
static if (is(T : MyClass!F, string F)) {
writeln(put method: , F);
} else {
static assert(0, Invalid type ' ~
std.traits.fullyQualifiedName!T ~ '.);
}
}
On Wednesday, 9 October 2013 at 04:31:55 UTC, Ali Çehreli wrote:
On 10/08/2013 03:12 PM, qznc wrote:
On Monday, 7 October 2013 at 17:57:11 UTC, Ali Çehreli wrote:
To look at just one usage example, the following line
carries two
requirements:
auto a = T();
immutable b = a;
1) b
On Wednesday, 9 October 2013 at 11:22:26 UTC, Colin Grogan wrote:
~/test$ ./mess ls
Executing: ls
STDOUT: mess
STDOUT: text.txt
Thats all fine, however, I'd expect it to print another
~/test$ at the end, as if its an interactive shell waiting
for input.
It is extracting the output of the
Dear,
I am looking D scientific paper to read it flirstly and maybe
cite it
I found some old paper here:
http://dl.acm.org/results.cfm?h=1cfid=369177407cftoken=46931292
thanks to report some link
On Wednesday, 9 October 2013 at 14:34:05 UTC, bioinfornatics
wrote:
Dear,
I am looking D scientific paper to read it flirstly and maybe
cite it
I found some old paper here:
http://dl.acm.org/results.cfm?h=1cfid=369177407cftoken=46931292
thanks to report some link
link's broken.
On Wednesday, 9 October 2013 at 14:27:30 UTC, Jesse Phillips
wrote:
On Wednesday, 9 October 2013 at 11:22:26 UTC, Colin Grogan
wrote:
~/test$ ./mess ls
Executing: ls
STDOUT: mess
STDOUT: text.txt
Thats all fine, however, I'd expect it to print another
~/test$ at the end, as if its an
Can someone explain why i can change Bar's immutable name member
please?
import std.stdio;
class Foo
{
public void change(string name)
{
name = tess;
writeln(name);
}
On 10/09/2013 08:26 AM, Gary Willoughby wrote:
Can someone explain why i can change Bar's immutable name member please?
import std.stdio;
class Foo
{
public void change(string name)
{
name = tess;
writeln(name);
}
}
On Wednesday, 9 October 2013 at 15:26:35 UTC, Gary Willoughby
wrote:
Can someone explain why i can change Bar's immutable name
member please?
import std.stdio;
class Foo
{
public void change(string name)
{
name =
On Wednesday, 9 October 2013 at 15:33:23 UTC, Ali Çehreli wrote:
On 10/09/2013 08:26 AM, Gary Willoughby wrote:
Can someone explain why i can change Bar's immutable name
member please?
import std.stdio;
class Foo
{
public void change(string name)
{
On Wednesday, 9 October 2013 at 04:41:35 UTC, Ali Çehreli wrote:
On 10/08/2013 03:03 PM, qznc wrote:
On Wednesday, 2 October 2013 at 13:09:34 UTC, Daniel Davidson
wrote:
1. If a variable is never mutated, make it const, not
immutable.
2. Make the parameter reference to immutable if that is
D does stripping of qualifiers from top level when creating a
copy which allows to pass immutable stuff as mutable parameter by
value. Adding any single level of immutable indirection will make
this impossible and result in compile-time error.
On Wednesday, 9 October 2013 at 15:46:29 UTC, Gary Willoughby
wrote:
So why does this give me an error i expect:
import std.stdio;
class Foo
{
public void change(string[] name)
{
name[0] = tess;
On Wednesday, 9 October 2013 at 15:33:23 UTC, Ali Çehreli wrote:
That string is independent from the argument (i.e. Bar.name).
They initially share the same characters. Either of those
strings can leave this sharing at will, and that is exactly
what name=tess does. 'name' now refers to
On Wednesday, 9 October 2013 at 16:02:43 UTC, Daniel Davidson
wrote:
Maybe this will help explain it:
void main() {
pragma(msg, typeof(Bar.name));
pragma(msg, typeof(Foo.change));
}
will print:
immutable(char[][])
void(string[] name)
The latter is really:
void(immutable(char)[] name)
The
Hi all,
I think this is not possible, but I'm using two different
templated libraries, and I'm wondering if there's a way of
adapting that:
module external.foo;
struct Foo { Foo[] foos }
module external.spam;
void spammer(T foolike){ foreach(s; foolike.spams){ ... } }
On Wednesday, October 09, 2013 16:13:48 Roman wrote:
In fact, since the template could be in a library, and code
could use that library well after the library has been
written...
As such, there is a fundamental conflict between how templates
work and how virtual functions work. They just
On Wednesday, 9 October 2013 at 15:50:55 UTC, Daniel Davidson
wrote:
void foo(const(MutableType) mt);
void foo(immutable(MutableType) mt);
Naturally the inclination is to choose the second as it is a
stronger guarantee that no threads are changing the data. Cool.
But wait, the first one still
import std.stdio;
struct Foo(T = int) { }
void main()
{
Foo f;
}
Error: Error: struct Foo(T = int) is used as a type
If I change Foo f into Foo!() f it works. Is the compiler not
able to see that this is not necessary, since I have a default
type?
On Wednesday, 9 October 2013 at 15:50:55 UTC, Daniel Davidson
wrote:
I would rephrase the second guideline as: Never dup or idup
an argument
to make it mutable or immutable, but require the caller to do
this
(might be able to avoid it).
Agreed. But it means you agree with me that immutable
I wondered the same thing a couple of weeks back. It seems to
work this way to avoid certain ambiguities. Related bug report /
discussion:
http://d.puremagic.com/issues/show_bug.cgi?id=1012
On Wednesday, 9 October 2013 at 14:54:32 UTC, Colin Grogan wrote:
is blocking. However, its not meant to be blocking is it not?
That new /bin/bash process is meant to run in parallel to the
main process?
I'm not sure exactly the implementation. But if you're asking to
run bash and then print
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