On Monday, 29 March 2021 at 01:39:16 UTC, Adam D. Ruppe wrote:
On Monday, 29 March 2021 at 01:24:13 UTC, Preetpal wrote:
writeln(isRandomAccessRange(arr));
Template arguments are passed by !(), not just ().
I believe you must also pass `typeof(arr)` since
isRandomAccessRange is only
On Monday, 29 March 2021 at 01:24:13 UTC, Preetpal wrote:
writeln(isRandomAccessRange(arr));
Template arguments are passed by !(), not just ().
I believe you must also pass `typeof(arr)` since
isRandomAccessRange is only interested in types.
This is a minimal example that re-creates the error message. I am
not understanding the error message that the compiler is giving
me. From my understanding, the compiler is saying that there is a
single possible candidate but it cannot figure out which one to
choose. Why would it not choose
