On Tuesday, 19 December 2017 at 10:37:05 UTC, Michael wrote:
On Tuesday, 19 December 2017 at 02:12:29 UTC, Mike Franklin
wrote:
On Tuesday, 19 December 2017 at 02:04:34 UTC, codephantom
wrote:
writeln(S.j);
// Error: Instance symbols cannot be used through types.
I don't understand why yo
On Tuesday, 19 December 2017 at 02:12:29 UTC, Mike Franklin wrote:
On Tuesday, 19 December 2017 at 02:04:34 UTC, codephantom wrote:
writeln(S.j);
// Error: Instance symbols cannot be used through types.
I don't understand why you would say that is a bug.
I meant that the example is wrong
On Tuesday, 19 December 2017 at 01:29:04 UTC, Meta wrote:
On Monday, 18 December 2017 at 23:44:46 UTC, Michael wrote:
[...]
I think the reason that this works is because i is static,
meaning that you don't need the `this` reference of S to access
it and thus it can be aliased. Declaring a st
On Tuesday, 19 December 2017 at 02:04:34 UTC, codephantom wrote:
writeln(S.j);
// Error: Instance symbols cannot be used through types.
I don't understand why you would say that is a bug.
I meant that the example is wrong, and a bug report should be
filed to fix the example.
Mike
On Tuesday, 19 December 2017 at 01:30:07 UTC, Mike Franklin wrote:
writeln(S.j);
// Error: Instance symbols cannot be used through types.
I don't understand why you would say that is a bug.
i.e.
//
import std.stdio;
struct S
{
int j;
}
void main()
{
writeln(typeof(S.j
On Monday, 18 December 2017 at 23:44:46 UTC, Michael wrote:
I have been looking at the following example found right at the
end of the section here:
https://dlang.org/spec/declaration.html#alias
struct S { static int i; }
S s;
alias a = s.i; // illegal, s.i is an expression
alias b = S.i; //
On Monday, 18 December 2017 at 23:44:46 UTC, Michael wrote:
Hello,
I have been looking at the following example found right at the
end of the section here:
https://dlang.org/spec/declaration.html#alias
struct S { static int i; }
S s;
alias a = s.i; // illegal, s.i is an expression
alias b =
On Monday, 18 December 2017 at 23:44:46 UTC, Michael wrote:
alias a = s.i; // illegal, s.i is an expression
Actually, as I understand it, the example provided in 10. is
legal (because it aliases a type), and the example provided in 3.
is illegal (because it aliases an expression)
perhaps t
On Monday, 18 December 2017 at 23:44:46 UTC, Michael wrote:
alias a = s.i; // illegal, s.i is an expression
alias a = s.i; (this is an alias to a type, since s.i is an int)
Hence it is actually 'legal', as far as I understand.
i.e... "AliasDeclarations create a symbol that is an alias for
