Hi,
I try to parse some hexadecimal numbers stocked in a string. So I
use this code
---
import std.conv;
string s = "B";
int value = parse!int(s, 16);
assert(value == 11);
---
But when I have several hexadecimal numbers in the string, and I
slice it, the compiler can't deduce which
On Saturday, 5 December 2015 at 22:05:11 UTC, anonymous wrote:
You can use std.conv.to instead or assign the slice to a
variable first.
This is a bit of a FAQ I think because people don't realize you
can use to and parse to do the same thing.
The big difference is parse will advance the
On Saturday, 5 December 2015 at 22:05:11 UTC, anonymous wrote:
On 05.12.2015 22:59, Quentin Ladeveze wrote:
---
import std.conv;
string s = "1B2A";
int value = parse!int(s[0..2], 16); //template std.conv.parse
cannot
deduce function from argument types !(int)(string, int)
---
Does someone
On 05.12.2015 22:59, Quentin Ladeveze wrote:
---
import std.conv;
string s = "1B2A";
int value = parse!int(s[0..2], 16); //template std.conv.parse cannot
deduce function from argument types !(int)(string, int)
---
Does someone have an idea of why it happens ? The version of parse that
is used
