Hi all,
The refactoring based on this discussion is done in SVN trunk. See this
issue for few more details:
http://restlet.tigris.org/issues/show_bug.cgi?id=361
I've also updated the 1.1 snapshot at:
http://www.restlet.org/downloads/1.1/current.zip
Best,
Jerome
Hi Thierry,
Thierry Boileau wrote:
on one hand, you define a "route" which binds all uris such as
"/users/{user}/birthday" to a new instance of the BirthdayResource
class.
On the other hand, the resource is in charge to perform the request,
that is to say return a representation (if any) in case
Hi Rob,
As a benefit of having the JCA process in place
(http://www.restlet.org/community/contribute), we can offer Restlet under
GPL v3 as well.
I've updated the web site to mention this new option:
http://www.restlet.org/about/legal
Best regards,
Jerome
> -Message d'origine-
> De
Jerome Louvel noelios.com> writes:
>
> Hi all,
>
> Maybe should also publish snapshots in the Maven repository? If we do
> so, we should follow the Maven naming conventions for version numbers.
>
> Note: we don't internally use Maven to build Restlet code base, but we
> know how to publish Mav
Hi Alex,
Thanks for sharing all the details.
1) For the root attachment issue, you can use this approach instead:
// To match only URIs that are strictly equal to "/"
Template template = router.attach("/", rootRestlet).getTemplate();
template.setMatchingMode(Template.MODE_EQUALS);
// To match
When I try to undeploy my restlet application from a running servlet
container it can't remove the deployed app completely because it seems
unable to delete com.noelios.restlet.jar from the exploded WAR contents.
I assume there is still some resource in use within the reference
implementation code
Hi Bruno,
on one hand, you define a "route" which binds all uris such as
"/users/{user}/birthday" to a new instance of the BirthdayResource
class.
On the other hand, the resource is in charge to perform the request,
that is to say return a representation (if any) in case of "GET"
requests, delete
Bruno Harbulot wrote:
I could try to write a patch, but since it may modify the API (or at
least the interfaces), it might be better if someone more experienced
with the code does it. I'm going to copy and paste all this in an RFE.
Here it is:
http://restlet.tigris.org/issues/show_bug.cgi?id=
Hi Jerome,
I haven't tried any code yet, but I think I found what was going on by
looking at some of the code. What I'm talking about is related to the
first modification mentioned in
http://restlet.tigris.org/issues/show_bug.cgi?id=281
(using getPeerCertificates()).
When using servlets, the
Hi all,
Maybe should also publish snapshots in the Maven repository? If we do
so, we should follow the Maven naming conventions for version numbers.
Note: we don't internally use Maven to build Restlet code base, but we
know how to publish Maven artifacts.
Best regards,
Jerome
2007/11/6, Thier
Hello,
I'd like to model resources using Restlet in a similar way as Section 12
of the tutorial ("Reaching target Resources"). As a simple example, I'd
like to map URIs like "/users/{user}/birthday" to read the full name of
a user from a database (or hash-table).
As far as I understand the t
Hi Jerome,
Regarding Jetty, AJP and the client certificates, I submitted a patch a
couple of days ago for Jetty, as there was a small bug:
http://jira.codehaus.org/browse/JETTY-457
I'm please to say Greg Wilkins (Jetty) has already incorporated the
changes in Jetty 6.1.6rc1.
I'll try to prov
Hello Jean-Yves,
the maven repository is located at the following URL: "maven.restlet.org".
But, at this time, no snapshot of release 1.1 has been published in
Maven since the first public release of restlet 1.1 will be delivered
in a few weeks (release 1.1 M1).
However a zip file can be downloade
I want to test latest development (of RESTlet 1.1), particularly JAXB
extension.
Where is the Maven repository to access latest SNAPSHOT of RESTlet 1.1 ?
Hello stack,
you can you use either DomRepresentation [1] or SAXRepresentation [2]
according to your preference with the following code (sample of POST
request) :
Client client = new Client(Protocol.HTTP);
Response response = client.post("http://localhost:80/essai/";, );
System.out.println(respon
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