object.add_child(...)
From: "pranay reddy"
To: "django-users"
Sent: Friday, July 6, 2018 6:12:44 AM
Subject: If any one have experience with Django treebeard package
Plz expalin how to add child for sibling
Sent via the [ http://play.google.com/store/apps/details?id=com.blackberry.hub
Point Apache at static_root.
Django apps you install may also include static files, and "collectstatic"
gathers all of those together and puts them in one place (under STATIC_ROOT).
From: "sarfaraz ahmed"
To: "Django users"
Sent: Wednesday, August 30, 2017 8:58:05 AM
Subject: Doubts abou
your form? I read somewhere on stackoverflow that Stripe Checkout wouldn't
accept the csrf token? Thanks again, Kristofen.
On Fri, Jun 17, 2016 at 4:49 PM, Kristofer Pettijohn < kristo...@cybernetik.net
> wrote:
This is how I did it. This is using Stripe Checkout.
forms.py ... (
This is how I did it. This is using Stripe Checkout.
forms.py ... (you can omit the address pieces if you don't need them)
class StripeForm(forms.Form):
stripeToken = forms.CharField(max_length=80)
stripeBillingName = forms.CharField(max_length=80, required=False)
stripeBillingAddressLine1 =
I recommend looking at the Django documentation. You set cookies via
request.session.set(). And you typically do not modify the response value
returned from HttpResponse() unless you are doing more advanced things.
For example (straight from the docs):
def post_comment(request, new_comment):
You need to name your URLs:
https://docs.djangoproject.com/es/1.9/topics/http/urls/#naming-url-patterns
urlpatterns = [
url(r'^doll/$', views.doll_describer),
url(r'^yourdolldata/(?P\d+)/$', views.yourDollData, name='yourDollData' ),
url(r'^connexion/$', views.connexion),
url(r'^logout/$',
Try changing file_url to be relative:
file_url = '/media/users/avatar.png'
Also check the nginx error log to make sure the path is being constructed
properly by nginx.
From: "Neto"
To: "Django users"
Sent: Thursday, March 31, 2016 11:04:07 AM
Subject: Django + Nginx + X-Accel-Redirect
I have also upgraded a few apps this way, from 1.5 to 1.9. Keep your eyes on
the release notes for each version for big changes. It also helps to have good
test cases written so that you can run them upon each upgrade.
From: "Gergely Polonkai"
To: "Django users"
Sent: Wednesday, March 30,
stro"
To: django-users@googlegroups.com
Sent: Wednesday, December 9, 2015 4:30:08 PM
Subject: Re: What am I supposed to do if I want a Wizard?
Thank you, Kristofer. It's interesting. I'm looking right now.
It seems complex, but I will investigate, although I would prefer a m
I sdid my own form wizard for a project I worked on. For a good example, you
can look at Oscar Ecommerce in github, and look at their checkout app within
the code. That may inspire you with some ideas on how to implement such a
behavior.
From: "Martin Torre Castro"
To: "Django users"
Sent
I think the login decorator may give you what you are trying to do in a much
easier way:
https://docs.djangoproject.com/en/1.7/topics/auth/default/#limiting-access-to-logged-in-users
Unless I am not understanding your issue.
From: "Juan Diego Gonzalez"
To: django-users@googlegroups.com
S
Your admin.py is specific to each app, on how you want the models for your app
to show up (or not show up) in the admin page.
Each app's admin.py will be unique to the models specific in that app.
The tutorial in the Django documentation shows a good example.
From: "Aliane Abdelouahab"
To
Also +1 for AWS. You can start out small for free for your first year, and grow
to the size of Pinterest over time. All of the other tools they provide are
helpful as well: RDS so you don't have to manage your own database, Caching
Service, Queuing Service, etc.
From: "Fred Stluka"
To: djan
This is a feature request that didn't make it into 1.7:
https://code.djangoproject.com/ticket/16735
From: "Lee Hinde"
To: django-users@googlegroups.com
Sent: Friday, January 2, 2015 7:34:59 PM
Subject: Change keys in values dictionary.
If I do a query:
messages =
Recipient.objects.fil
thy W. Cook wrote:
>
> Yes it is possible and quite easy to do. Take a look at
> https://docs.djangoproject.com/en/1.6/ref/contrib/admin/actions/
>
> Cheers,
> Tim
>
>
> On Sat, Oct 26, 2013 at 12:17 AM, Kristofer Pettijohn <
> kris...@cybernetik.net > wrote:
&g
I am using the following type of model setup:
class Product(models.Model):
name = models.CharField(max_length=40)
description = models.TextField(blank=True)
active = models.BooleanField(default=True)
priority = models.IntegerField(default=100)
size_chart = models.ForeignKey(SizeChart)
desig
Hello,
I remember seeing this some time ago, but can't remember what it is called or
where it is in the documentation.
I am looking for the feature that allows for a field to reference a key in
multiple tables.
For example, lets say I have several models: User, Address, Message. Each of
these
27;m not
sure where else I can access the required form steps and also be able to raise
a validation error.
- Original Message -
From: "Babatunde Akinyanmi"
To: "Kristofer" , django-users@googlegroups.com
Sent: Friday, January 11, 2013 8:05:59 AM
Subject: RE
Hello,
I am using FormWizard with a 12-step form.
On step 6, I want to perform verification on a field but it depends on fields
that were entered in steps 2-5.
I cannot figure out how to get data from the previous steps in the form
validation for step 6.
Where is a point in the FormWizard
ginal Message -
From: "Kristofer"
To: django-users@googlegroups.com
Sent: Wednesday, January 9, 2013 12:49:28 AM
Subject: Admin and ForeignKey
Hello,
I have three models, defined like the following (code below simplified):
class Shirt(Model):
sku = CharField()
descript
Hello,
I have three models, defined like the following (code below simplified):
class Shirt(Model):
sku = CharField()
description = CharField()
class Color(Model)
name = CharField()
shirt = ForeignKey(Shirt)
price = Decimal()
class Order(Model)
shirt = ForeignKey(Shirt)
color = Forei
Hello,
I am using FormWizard with SessionWizardView.
The form is working as expected by using the submit or previous buttons,
but if the user goes to a different link on the site, and then back to
where the form was, the form starts out fresh. I have verified with
Developer Tools that the br
I just wanted to drop a little praise to everyone who has contributed to Django
over the years.
I worked on a project about a year ago, and did it exclusively in CakePHP. I
can't go into too many details about what the project is due to privacy
concerns, but it revolved around customer self-se
Hello,
I'm new to Django and trying to learn it by making a simple budget/checkbook
application.
I apologize for my ignorance, but I couldn't seem to find an answer to this on
Google or the Django docs from my searches.
I want to create a function that will take a bank account as an id numb
> That is substantially harder, but could be possible. The main problem is that
> the Django ORM will want to write SQL queries when there's a link to the
> EmailAccount model.
>
> Your best bet is probably a proxy model that contains a reference to the
> relevant API record (e.g. the email add
ogether with managed=True.
You may still face some issues, however I think this should be
possible.
Cheers,
Filip
On 20 srp, 12:51, Malcolm Box wrote:
> On 20 August 2011 02:33, Kristofer Pettijohn wrote:
>
> > Hello,
>
> > Is it possible to create specific models without a da
Hello,
Is it possible to create specific models without a database table?
Basically what I would like to do is create an email account management
application that ties into my existing mail server and its API. I would like
Django to have a Users model and keep track of users, a Domains model
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