Suppose, you want to have a model, the fields of which are available
in multiple languages. How would you people go around doing it? The
most trivial method would be to define as many variations of each text
field as there are lanugages, and define a function inside the model
that returns the vari
Yay another fitness app based on django!
http://code.google.com/p/fiteat/
On May 3, 9:15 am, Greg Taylor <[EMAIL PROTECTED]> wrote:
> I was wondering if there's any reason why get_FOO_display() calls
> aren't being evaluated when updating/adding new objects via the admin
> interface. What I mean
laces the
field's _choices property with the options sorted to my liking. I can
provide the necessary code samples, if anyone is interested.
On Apr 25, 11:57 pm, dimrub <[EMAIL PROTECTED]> wrote:
> 2. Is there a way to sort the order of the choices dynamically (e.g.,
> based on the
What you can try out is the following approach (a variation of which I
use in order to customize the data being presented based on the
identity of the currently logged in user).
1. Create a middleware that pushes the relevant info from the request
into a thread local storage.
2. Create a custom m
In addition to the above, you can have a field in your model, that
will contain that sum, and update it in your save(). It may not be as
beneficial with sum() as it is with some other functions that work on
multiple rows.
陈亮 wrote:
> Hi there,
> I've googled a lot on how to get the sum of a i
_field.options[i].text == 'Other') {
other_index = i;
}
}
if (type_field.addEventListener) {
type_field.addEventListener("change", change_handler, false);
} else if (type_field.attachEvent) {
type_field.attachEvent("onchange", change_handler
On Apr 25, 11:57 pm, dimrub <[EMAIL PROTECTED]> wrote:
> Greetings, all!
>
Oh, forgot to mention: I'm trying to use admin views. I do realize
question #2 has a trivial solution if a non-admin view is used (and,
come to think of it
Greetings, all!
Two (possibly - trivial) questions regarding a field that has
'choices' defined for it.
1. Is there a way to specify a special choice, upon which another
field becomes active? A typical use case is to have a certain set of
predefined values (out of which the user will USUALLY cho
I don't think having a function with such a profound side effect (such
as making clean_data available) is a good idea. Very counter-
intuitive, IMHO. Why not split it into two:
- validate() - that performs the validation and makes clean_data
available
- is_valid() - that calls the above validate(
The most obvious way would be to override the corresponding template
to include only a specific list of apps.
On Apr 22, 8:22 pm, "Monica Leko" <[EMAIL PROTECTED]> wrote:
> Hi
>
> Can I somehow exclude sites and auth from admin index page, and left
> only django apps?
--~--~-~--~~
(I will continue talking to myself here for a while)
So, I've located the key passage in the django book:
== quote ==
Another implication is that the permission system, while powerful, has
no support for limiting access on a per-object basis as of this
writing. If you trust someone to edit his o
OK, I seem to have found a way to achieve the first task, even though
it doesn't seem to be a rather elegant one. Here's the code that I
wrote for it:
from django.contrib.admin.views.main import change_list
def index(request):
# Copy the GET dict in order to modify it
g = request.GET.cop
Hi, all!
I am fairly new to Django, but I think I've looked rather thoroughly
at the available documentation, and couldn't come up with an answer,
so I'll ask here, and please forgive me if it's a FAQ.
I would like to do basically two things, both are related to the admin
views and to users. The
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