Great blog post.
Michael
On 4/20/07, Malcolm Tredinnick <[EMAIL PROTECTED]> wrote:
>
> On Fri, 2007-04-20 at 22:26 +0100, Oliver Charles wrote:
> > Just write your own view that in turn calls a generic view? Create a new
> > view, with a similiar signiture, but change the object_id for team_id
>
On Fri, 2007-04-20 at 22:26 +0100, Oliver Charles wrote:
> Just write your own view that in turn calls a generic view? Create a new
> view, with a similiar signiture, but change the object_id for team_id
> AND result_id. Then, do a bit of logic to find the query set you need a
> view of, and pa
On 4/20/07, DuncanM <[EMAIL PROTECTED]> wrote:
>
> (r'^team/(?P[0-9]+)/results/(?P[0-9]+)/$',
> 'django.views.generic.list_detail.object_detail', dict(results_dict,
> template_name='teams/team_results_reports.html')
>
> doesn't work for me...
Uh, yeah, it wouldn't would it? Sorry, about that.
On 4/20/07, DuncanM <[EMAIL PROTECTED]> wrote:
>
> Hi Karen,
>
> (r'^team/(?P[0-9]+)/results/(?P[0-9]+)/$',
> 'django.views.generic.list_detail.object_detail', dict(results_dict,
> template_name='teams/team_results_reports.html')
FWIW, django views are pretty simple to do yourself, and you can
st
Hi Karen,
(r'^team/(?P[0-9]+)/results/(?P[0-9]+)/$',
'django.views.generic.list_detail.object_detail', dict(results_dict,
template_name='teams/team_results_reports.html')
doesn't work for me, but I've been thinking about your post, and you
were right about me wanting to leave breadcrumbs (why co
Do you really need the team_id to specify the result you are looking for?
I'm guessing you probably have a single results table (with results from all
teams), and the 2nd number in the url is all you need to select the result
in question. Then:
(r'^team/(?P[0-9]+)/results/(?P[0-9]+)/$',
'django.v
Just write your own view that in turn calls a generic view? Create a new
view, with a similiar signiture, but change the object_id for team_id
AND result_id. Then, do a bit of logic to find the query set you need a
view of, and pass this through to a generic view, and then return this.
Hope th
Thanks for the help Tim, however I've tried that and it doesn't work :
(
Is there any other way you could think of achieving it, even if it
doesn't use generic views and urls?
Thanks,
Duncan
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> (r'^team/(?P[0-9]+)/results/(?P[0-9]+)/$',
> 'django.views.generic.list_detail.object_detail', dict(results_dict,
> template_name='teams/team_results_reports.html')),
>
> the bottom Url is totally wrong I just had a stab in the dark (a
> rather poor one at that) but it was attempting to il
Firstly: there are many teams, each team can have many results.
so obviously you'd need an id for the result id as well not just team/
1/results/detail.
Sorry it was a bad example in the previous post, it could be team/3/
results/5/ or team/10/results/522 (i.e. the team and results numbers
aren
On 4/20/07, DuncanM <[EMAIL PROTECTED]> wrote:
> I'm stuck when trying to do:
> team//results/
> which I'd like to return a page that gives the detail of a result.
Sorry, this isn't clear to me.
You're saying something like team/1/results/1/?
If so, why repeat the 1?
Why not team/1/results/deta
Hi,
I have looked at the django docs and couldn't find anything exactly
related to what I want to do. I have my urls set up currently so:
team/
returns a page for that team
team//results
returns a results page for that team
I'm stuck when trying to do:
team//results/
which I'd like to return
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