Re: What would be a better views.py code to achieve this particular task .

I'm afraid I can't help you any further on this, as I don't know enough about the contenttypes framework, and I still don't really understand what it is you are asking. Cal I got it fixed . Now I have smaller issue . Foreign key ( of a particular model) is returning me a table_id with some rand

Re: What would be a better views.py code to achieve this particular task .

Again, please keep your replies on-list. I'm afraid I can't help you any further on this, as I don't know enough about the contenttypes framework, and I still don't really understand what it is you are asking. Cal On Thu, Jun 23, 2011 at 10:07 PM, Satyajit Sarangi < writetosatya...@gmail.com> wr

Re: What would be a better views.py code to achieve this particular task .

Please keep your replies on-list so others may benefit in the future. On Thu, Jun 23, 2011 at 10:01 PM, Satyajit Sarangi < writetosatya...@gmail.com> wrote: > First of all , when I am doing this > perm.table = ContentType.objects.get(app_label="OsmMap",model="Osm_Layers") > I am getting a content

Re: What would be a better views.py code to achieve this particular task .

You're going to have to explain this a lot better, because I really did not understand what you mean. At a *GUESS*, are you trying to prevent against db save race conditions or something?? Please clarify. Cal On 23/06/2011 20:07, Satyajit Sara

What would be a better views.py code to achieve this particular task .

This is my models.py of a different app . class PermiLayer(models.Model): user = models.ForeignKey(User) table = models.ForeignKey(ContentType) permi = models.IntegerField() In another app's views , I am accessing a form that has given me a username . I have to chec