After some testing i think that the prob occurs because from the same view
I render another one form in the same template. This form is not
multi-part. In this case it happens what I describe. If i put this simple
form in comments (in views and in template) the multipart form uploads the
file n
>
> I'm running it on the django development server. I changed the header and
> it behaves the same way. Is that expected or not?
>
I also tried print request.FILES and I get , but after
> i tried print request.raw_post_data and it seems that the name of the file
> that i try to upload is incl
Sorry about that. I accidentally over-looked where you mentioned that in
your email.
Are you running this on a debug server? Also, can you try replacing your
template code with a simple {% csrf_token %}{{ form }} and see if that makes any differences?
On Mon, Sep 10, 2012 at 10:38 AM, mapapage w
>
> I have it like this, with filefield, in my first question I'm just posting
> the generated model from inspectdb and underneath I'm saying that I change
> it to FileField..
>
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ahh, sorry I just saw something that might help. Try making this change:
docpath = models.CharField(max_length=200)
to:
docpath = models.FileField(...) # Check the docs for arguments to this
Field. https://docs.djangoproject.com/en/dev/ref/models/fields/#filefield
On Mon, Sep 10, 2012 at 8:41 A
>
> as I say in my last reply, I include the multi part header and it doesn't
> work! :( What else I can try?
>
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Also, don't forget the multi-part in your template:
On Sun, Sep 9, 2012 at 2:29 PM, Joseph Mutumi wrote:
> I'm assuming you are using the forms.ModelForm for your model? Say
> LicenceForm?
>
> class LicenseForm(forms.ModelForm):
> class Meta:
> model = License
>
> According to the d
Yes, exactly I'm using a modelform and in my views I'm doing:
def upload(request):
if "doc-form" in request.POST:
docform = LicenceForm(data=request.POST, files=request.FILES)
if docform.is_valid():
docform.save()
return render_to_response('bingo.html',
I'm assuming you are using the forms.ModelForm for your model? Say
LicenceForm?
class LicenseForm(forms.ModelForm):
class Meta:
model = License
According to the doc you have to pass all relevant QueryDicts to the form
__init__
when you are creating a bound instance. In a nutshell make
Hi! It's my first time trying to achieve the ''file upload functionality'
and I need your help. I'm working on a legacy db and I'm supposed to do the
file upload in a table that gets created this way:
CREATE TABLE "LICENCE"
("ID" NUMBER NOT NULL ENABLE,
"VEH_ID" NUMBER NOT NULL
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