> and then make these accessible in some random template using somthing like
> the following:
>
> Can anyone suggest a good way of doing this?
>
1) write your own context_processors
http://docs.djangoproject.com/en/dev/ref/templates/api/#writing-your-own-context-processors
2) write your own templ
I have a bunch of regular site paths that I'd like to be able to refer to
both in my Python code and in my templates, e.g.
settings.py:
site_root = "/portal"
contact_url = site_root + "/contact"
sitemap_url = site_root + "/sitemap"
login_url = site_root + "/account/login"
logout_url = site_root
hi,
I have an app which is being used to conduct an annual event. The app lives in
the 'web' directory of the project and is named 'web'. I serve the app from
root - that is, home is at:
http://mysite.com/home/
http://mysite.com/web/home/ also works
I now need to serve this from:
http://mysi
On Thursday 20 Oct 2005 4:56 pm, Andy Shaw wrote:
> > {{ site_url }}/css/layout.css.
> > how do i do this?
>
> Um... I don't know the actual answer to your question off the bat,
> but you can use an absolute URI that doesn't contain the site name:
thing is that i have one copy of the app on my lo
Kenneth Gonsalves wrote:
hi,
i know it must be somewhere, but cant find it. How do you refer to the
site url in a template? Say my css file is in
http://mysite.com/css/layout.css, to make this portable i would have to
make the template as:
{{ site_url }}/css/layout.css.
how do i do this
hi,
i know it must be somewhere, but cant find it. How do you refer to the
site url in a template? Say my css file is in
http://mysite.com/css/layout.css, to make this portable i would have to
make the template as:
{{ site_url }}/css/layout.css.
how do i do this?
--
regards
kg
http
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