Yes there is a difference. The 'common' lead is the correct one. The other one will 'work', but
you have to use a specific crystal switch position, with the other just any 'open' position works.
The 'other' lead bypasses the amplifier and connects the FS-4 RF to the feedback link of the
Hi Guys,
I have an IQPro VFO that I built for a Direct conversion receiver I am
building. It is a 9854 based DDS VFO designed by Craig AA0ZZ. I have
decided to go a different route with the DC receiver LO.
That leaves me with a perfectly good VFO to find a use for. I thought
that maybe it
Bob -
Not particularly difficult. You need about 2-3 V p-p from it, maybe less, which means you may need
a transistor, or possibly an MMIC. I'm not familiar with the IQPro, but for this duty you'll need
to cover from about 11.6 to 40.6 MHz in 500 khz steps. It would be more convenient if
I'm curious Garey about why not the other lead? It just shouldn't be
grounded? Maybe a 0.01 in series with the shield side? Or, couldn't he do a
6:1 balun and a 2 cond. shielded cable? (Admittedly, it's more work than
simply one side of the socket and chassis ground.) His impedances would
match
Ed -
Because the crystal socket is in 'series' with the Emitter of the BAND oscillator transistor. The
'bus' that ties all the sockets together is the Emitter, the Base is bypassed to ground, and the
Collector is the output.
Unless he's short on drive voltage, he may not need any
I am curious too - if I am interfacing an FS-4 to an R4B (or even a C or an
SPR-4) which pin on the crystal socket do I plug into? The manual does
indicate there is a difference between either pin on the crystal socket -
just plug it in and ground the outer shield.
Thanks
Steve KD2ED
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