Re: E as a % of a standard deviation

I suppose like you say that when you factor in stratification and clustering, it isn't such a no brainer as in my example. Thank you again for enlightening me. "Donald Burrill" <[EMAIL PROTECTED]> wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... &g

Re: E as a % of a standard deviation

It is simply amazing to me that you can do a random sample of 4,147 people out of 50 million and get a valid answer. What is the reason for taking mulitple samples of the same n - to achieve more accuracy? Is there a rule of thumb on how many repetitions of the same sample you would take? "Jo

Re: E as a % of a standard deviation

oughts given my clarification, I would welcome your insights. "Donald Burrill" <[EMAIL PROTECTED]> wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... > On Fri, 28 Sep 2001, John Jackson wrote in part: > > > My formula is a rearrangement of the confidence in

Re: What is a confidence interval?

Great explanation "dennis roberts" <[EMAIL PROTECTED]> wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... > At 02:16 AM 9/29/01 +, John Jackson wrote: > > >For any random inverval selected, there is a .05% probability that the > >sam

Re: What is a confidence interval?

How do describe the data that does not reside in the area described by the confidence interval? For example, you have a two tailed situation, with a left tail of .1, a middle of .8 and a right tail of .1, the confidence interval for the middle is 90%. Is it correct to say with respect to a value

Re: E as a % of a standard deviation

f mu with our sample mean the > population standard deviation or sigma were 15? > >n = ((1.96 * 5) / 3)^2 = about 11 ... > > only would take a SRS of about 11 to be within 3 points of the true mu > value in your 95% confidence interval > > unless i made a

Re: E as a % of a standard deviation

s, ie. 300 m or can you solve it another way. It was suggested you can express the SD as a fraction of the E. ie. E = SD/2. "Randy Poe" <[EMAIL PROTECTED]> wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... > John Jackson wrote: > > > the forumla I was

Re: Confidence intervals

I am interested in how to describe the data that does not reside in the area described by the confidence interval. For example, you have a two tailed situation, with a left tail of .1, a middle of .8 and a right tail of .1, the confidence interval for the middle is 90%. Is it correct to say with

Re: Translating Error of estimate into fraction of Sigma

This is a better example than the apples (I hope). This time is their is a n=x provided. "Jay Warner" <[EMAIL PROTECTED]> wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... > "@Home" wrote: > > > I have estimation of mean / confidence level problem with very litte data > > to go on

Re: What is a confidence interval?

this is the second time I have seen this word used: "frequentist"? What does it mean? "Radford Neal" <[EMAIL PROTECTED]> wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... > In article <[EMAIL PROTECTED]>, > Dennis Roberts <[EMAIL PROTECTED]> wrote: > > >as a start, you could relate e

Re: E as a % of a standard deviation

2 and attempting to express .05 as a fraction of a std dev. "Glen Barnett" <[EMAIL PROTECTED]> wrote in message 9oug3c$su1$[EMAIL PROTECTED]">news:9oug3c$su1$[EMAIL PROTECTED]... > > John Jackson <[EMAIL PROTECTED]> wrote in message > MGns7.49824$[EMAIL PR

Re: error estimate as fraction of standard deviation

Thanks for the formula, but I was really interested in knowing what % of a standard deviation corresponds to E. In other words does a .02 error translate into .02/1 standard deviations? "Graeme Byrne" <[EMAIL PROTECTED]> wrote in message 9orn26$m80$[EMAIL PROTECTED]">news:9orn26$m80$[EMAIL PROT

E as a % of a standard deviation

re: the formula: n = (Z?/e)2 could you express E as a % of a standard deviation . In other words does a .02 error translate into .02/1 standard deviations, assuming you are dealing w/a normal distribution? = Instr