On 12/14/2012 08:26 AM, ⸘Ŭalabio‽ wrote:
2012-12-13T06:53:10, Kristofer Munsterhjelm:
- If the voters know that +99 and -99 will be discarded, that
effectively turns +99 and -99 into 0. Thus they'd not use those values,
instead knowing their "real maxima" to be +98 and -98.
Yes, but
On 12/13/2012 11:31 AM, Kristofer Munsterhjelm wrote:
On 12/13/2012 05:28 PM, Chris Benham wrote:
Of the various proposed ways of weighing "defeat strengths" in
Schulze, Losing Votes is the one that elects most from the "tops of
the ballots". Given that we are seeking to convert supporters of F
How would that work using the other formula?
(I know I'm kinda just being lazy here, but I think other people would be
interested.)
Jameson
2012/12/14 Ross Hyman
> example using entropy formula
> two parties that split the vote equally:
> 1/2 , 1/2 effective number of parties n_a=2
> One o
example using entropy formula
two parties that split the vote equally:
1/2 , 1/2 effective number of parties n_a=2
One of these parties divides equally:
1/2, 1/4, 1/4 effective number of parties n_b= 2sqrt(2)
now the other party also divides equally:
1/4, 1/4, 1/4, 1/4 effective number of p
Consider that there are a number of parties, with the ith party having
vote fraction P_i. Now consider that you can divide the parties into
two, left parties and right parties. Call the vote fraction for the left
parties P_L and the vote fraction for the right parties P_R. Use the
effective n
Interesting. When is it different from the other formula?
Jameson
2012/12/13 Ross Hyman
> Here is a physics alternative to the "effective number of parties"
> formulas mentioned on the Wikipedia page:
> http://en.wikipedia.org/wiki/Effective_number_of_parties
>
> Based on the concept of entropy
