Greetings,
For those of you who are interested in attending the Colorado Product Safety
Technical Committee (CPSTC) meeting, please read on.
Quick summary
Date : January 12, 2000
Time : 6:30pm
Location: Jackson's All American restaurant in Thornton, Colorado.
Just off of I-25 o
Hi Anil,
I regularly achieve speeds in excess of 150kbits/sec (or is it K, oh
well) dowloading plain text log files from my website over a "56k"
modem. This is possible because most modern modems do compression
which works very well on text files and bmp impages, and not very well
on jpeg images
Anil Allamaneni wrote:
>
> I might have "faux-pas"ed (nice way of saying, "screwed up"). Apologies!
>
Hi Anil,
No harm done.
There is a modem speed test at
http://www.computingcentral.com/topics/bandwidth/ .
Click on "Bandwidth Speed Test" and try it out.
--
==
I might have "faux-pas"ed (nice way of saying, "screwed up"). Apologies!
-Original Message-
From: owner-emc-p...@ieee.org [mailto:owner-emc-p...@ieee.org]On Behalf
Of Dan Kwok
Sent: Friday, January 07, 2000 8:03 PM
To: Anil Allamaneni; EMC-TSTC Group
Subject: Re: Y3K
Anil Allamaneni
At 12:58 AM 08/01/2000 , you wrote:
I saw a CPS to Hz conversion chart in a military (AF) test report back in
the 70s.
The 'X' axis (CPS) was decimal and the 'Y' axis (Hz) was Log.
It provided an interesting conversion curve. It even had a formula to do
the conversion long hand.
We need
Ralph Cameron wrote:
>
> Hans and Dan:
>
> You're overlooking the fact that by definition in modern computers a byte =
> 8 bits so when they say 100Mb drive they mean exactly that, 100 megabytes =
> 800 megabits capacity. ( if you ignore the parity bit which is seldom
> transmitted or recorded
Anil Allamaneni wrote:
>
> I dont think this is right. There are times when my modem says data is being
> transferred at 10k/s. So does that mean actual throughput is 10x8 = 80kbps
> from a 56kbps modem ?? Data transfer over an analog line would essentially
> depend on your line and the distance
Hans and Dan:
You're overlooking the fact that by definition in modern computers a byte =
8 bits so when they say 100Mb drive they mean exactly that, 100 megabytes =
800 megabits capacity. ( if you ignore the parity bit which is seldom
transmitted or recorded.). .
A 56K modem downloads files a
I dont think this is right. There are times when my modem says data is being
transferred at 10k/s. So does that mean actual throughput is 10x8 = 80kbps
from a 56kbps modem ?? Data transfer over an analog line would essentially
depend on your line and the distance from CO (besides your system).
Re
kHz should stay this way, I think the large "K" was some kind of
marketing abuse
milli should still be small "m"
micro should use a small "u"
:-)
rehel...@mmm.com wrote:
> Recall it? I still use it !
>
> ===
>
> m...@cjbdev.demon.co.uk (Mark) on 01/07/2000 0
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