Hi Marie,
But division by 5 would give the average area of the 5 mid slices. Maybe
that is even more meaningful (reliable) than just a single slice.
Best, Martin
On 04/14/2013 09:05 AM, Bruce Fischl wrote:
Hi Marie,
no, that won't account for variability across slices in the l/r
direction.
Hi Marie,
no, that won't account for variability across slices in the l/r
direction. Try rerunning mri_cc with -t 0 (thickness) and see if it
generates a cc in just the midsagittal plane
cheers
Bruce
On Sun, 14 Apr 2013, Marie Schaer wrote:
Hi Bruce,
Thanks for your response. Then I
Hi Marie
It is mm^3 of I believe a 5 mm thick cc. We don't measure the thickness by
default
Cheers
Bruce
On Apr 13, 2013, at 2:18 AM, Marie Schaer marie.sch...@unige.ch wrote:
Hi Bruce,
Thanks for your response. My question was indeed: what is the unit of the
CC_* output in the
Hi Bruce,
Thanks for your response. Then I assume that I can divide these values by 5 and
present them as area of the CC on the midline section, right?
Have a nice week-end,
Marie
On Apr 13, 2013, at 5:18 AM, Bruce Fischl
fis...@nmr.mgh.harvard.edumailto:fis...@nmr.mgh.harvard.edu wrote:
Hi all,
I have a quick question related to the corpus callosum segmentation: I read in
previous posts that the reference explaining more about the CC subdivision in 5
segments was the one by Rosas et al, Neuroimage 2010. But in this publication,
you show thickness of the corpus callosum as
