Re: [Gambas-user] Collections

2010-01-16 Thread nospam.nospam.nos...@gmail.com
2010/1/16 Pino Zollo pinozo...@gmail.com: The two print statements print exactly the same thing...the Lista.key is correct and all different, but the other ( ; Element[1];;   ;; Element[0] ) print always the last element added to the structure. First you need to sort out if you have a

Re: [Gambas-user] Collections

2010-01-16 Thread Charlie Reinl
Am Samstag, den 16.01.2010, 07:23 -0300 schrieb Pino Zollo: Il venerdì 15 gennaio 2010 17:39:14 hai scritto: Am Freitag, den 15.01.2010, 16:04 -0300 schrieb Pino Zollo: DIM Dict AS NEW Collection DIM Element AS String Dict[Blue] = 3 Dict[Red] = 1 Dict[Green] = 2 FOR EACH

Re: [Gambas-user] Collections

2010-01-16 Thread Werner
On 16/01/10 18:23, Pino Zollo wrote: Il venerdì 15 gennaio 2010 17:39:14 hai scritto: Am Freitag, den 15.01.2010, 16:04 -0300 schrieb Pino Zollo: DIM Dict AS NEW Collection DIM Element AS String Dict[Blue] = 3 Dict[Red] = 1 Dict[Green] = 2 FOR EACH Element IN Dict PRINT

Re: [Gambas-user] Collections

2010-01-16 Thread Pino Zollo
Il sabato 16 gennaio 2010 08:25:56 hai scritto: Salut Pino, my problem with your problem is: That is just a piece of code, I can only run and debug, if I invent ALL the rest. And so,every test will say nothing(if it is not a typo in that piece code). So please sent always a full run able

Re: [Gambas-user] Collections

2010-01-16 Thread Pino Zollo
Il sabato 16 gennaio 2010 12:21:09 gambas-user-requ...@lists.sourceforge.net ha scritto:               Disp.DisRes.Text = Disp.DisRes.Text ~             INC i          LOOP          ' CBCommand.Clear          ' CBComm2.Clear          FOR EACH Element IN Lista              

Re: [Gambas-user] Collections

2010-01-16 Thread Werner
On 17/01/10 00:27, Pino Zollo wrote: Il sabato 16 gennaio 2010 12:21:09 gambas-user-requ...@lists.sourceforge.net ha scritto: Disp.DisRes.Text = Disp.DisRes.Text ~ INC i LOOP ' CBCommand.Clear ' CBComm2.Clear FOR

Re: [Gambas-user] Collections

2010-01-16 Thread Fabien Bodard
just don't forget when you add multiple array, think to add new array as only the memory address is added to the collection , not the array content. In other case all the array in the collection link to the same one dim mycol as NEW collection dim i as integer dim aText as string[] For i = 0 to

[Gambas-user] Collections

2010-01-15 Thread Pino Zollo
Hi, please can somebody explain the following from the documentation: DIM Dict AS NEW Collection DIM Element AS String Dict[Blue] = 3 Dict[Red] = 1 Dict[Green] = 2 FOR EACH Element IN Dict PRINT Element; NEXT hr3 1 2 -- 3,1 and 2 are Integer, so why Element is a String and