On Sat, 24 Dec 2016 11:05:00 +0100
Benoît Minisini wrote:
> Le 24/12/2016 à 09:44, Fabien Bodard a écrit :
> > Public Sub Main()
> >
> > Dim s As String
> > Dim i As String
> > Dim a As New Integer[]
> > ''1) with no knowledge of the number of values
> > 'init the string
> > s = "[12,
An elegant solution, one just has to love the Gambas language!
a.Add(i) is the part I overlooked, it takes a while to change one's old habits.
To all, have a Great Christmas. In this part of South Africa there is a
heatwave with temperatures into the high thirties for Christmas.
On 24/12/2016, B
Le 24/12/2016 à 09:44, Fabien Bodard a écrit :
> Public Sub Main()
>
> Dim s As String
> Dim i As String
> Dim a As New Integer[]
> ''1) with no knowledge of the number of values
> 'init the string
> s = "[12,32,3]"
>
> 'remove unused spaces and braquets
> For Each i In Split(Left(R
Public Sub Main()
Dim s As String
Dim i As String
Dim a As New Integer[]
''1) with no knowledge of the number of values
'init the string
s = "[12,32,3]"
'remove unused spaces and braquets
For Each i In Split(Left(Right(Trim(s), -1), -1))
a.Add(i)
Next
'display the arr
Baffled!
I have a string, like "[1,3]", that I want to populate an integer array from.
How to?
tia
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B Bruen
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