Absolutely brilliant, the deferred command worked like a charm.
Many thanks to all of you!
-G
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Unfortunately, I need the width and height of the area because I append
that information on a url.
I will try the deferred command and let you know.
Many thanks,
G
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You don't need getOffsetHeight to achieve what you want. There are two
solutions:
1. Use LayoutPanel instead of DockLayoutPanel. LayoutPanel allows you
to add two widgets that occupy the same space. If you don't specify
the position of each child widget, each child widget will occupy the
entire sp
getOffsetHeight/Width only returns a value other than 0 if the element has
been successfully rendered by the browser (possibly including elements that
have visibility:hidden css).
When you call DeckLayoutPanel.setWidget(w) the DeckLayoutPanel schedules a
layout command which will be executed af
The problem is that I call getOffsetHeight/Width on a panel which belongs
to a widget which has display property set to none. The display property is
set to none because that widget is not currently displayed by the
decklayoutpanel but it is attached to it, which is the desired behaviour.
I a
Use firebug to analyze your problem.
If it's your display property then change this by
widget.getElement().getStyle().setDisplay(Display.BLOCK) (can be
little different).
By default the Display property is set to auto so if you aren't
setting it, it wouldn't give you any problem.
On Nov 30, 1:19
t @Vitrums
I am convinced that my problem is caused because the property display is
set to none, however I don't know how to solve it.
I could add an AnimationCallback on the decklayoutPanel to find out when
the widget is finally being displayed, but that kinda defeats the use of
Activity.st
Thank you for your suggestions, however, the display property is not set to
none, actually is not set at all.
Thanks,
G
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Make sure your widget is attached (check the attached property) before
requesting the widget for any dimensions.
Example: in my animation components I always first check that the
widget is attached as otherwise the animations are based on (most of
the time) incorrect dimensions as the browser didn
getOffsetHeight() of an element which *display* property was set to *none*will
always return 0
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>From what I have found is the objects need to be visable in the
Document object first.
So try this:
public static void adjustHeight(final DockLayoutPanel topPanel, final
SimplePanel bodyPanel, final DockLayoutPanel outerPanel, final boolean
isIpad)
{
Scheduler.get().scheduleDeferred(new
Hi group,
Consider an application which has a *DeckLayoutPanel* as a shell, and has
two DockLayoutPanel as children, which means only one child is shown at any
time. I am using MVP with Activities and Places, there are two places and
each place corresponds to displaying a child.
When the app
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