Re: [Gretl-users] Loop question

2010-05-25 Thread Jack
On Tue, 25 May 2010, Henrique Andrade wrote: > Now, because I just need the values for 6, 12 and 24, I'm trying to > substitute the second line "loop for (n=6;n<=24;n=n*2)" for this: > > loop for (n=6;n=12;n=24) > > But the script isn't working. Any hints? This, maybe? scalar m = 3 scalar bas

Re: [Gretl-users] Loop question

2010-05-25 Thread Kehl D ániel
Dear Henrique, you have to simply follow the syntax. Take a look at Chapter 9 in the User's Guide (Help/User's guide in the menu). Simple example on page 60 will help! Best wishes Daniel -Original Message- From: Henrique Andrade To: Gretl list List-Post: gretl-users@gretlml.univpm.it

Re: [Gretl-users] Loop question

2010-05-25 Thread Hélio Guilherme
Hi Henrique, I believe that this does what you want: loop for (n=6; n<=24; n*=2) --quiet No other simple options. On Tue, May 25, 2010 at 8:53 PM, Henrique Andrade wrote: > Dear Riccardo, Kehl and Artur, > > Thanks a lot for your help! I'd tried all the options you gave me and > my final scrip

Re: [Gretl-users] Loop question

2010-05-25 Thread artur bala
Or, if your index is something like of a geometric series as it seems to be (let's say 6, 12, 24, 48, and so on) and too long to do manually you can try this one: scalar count=0 loop for (count=6;count<=24;count=count*2) --quiet endloop <\script> cheers, artur Riccardo (Jack)

Re: [Gretl-users] Loop question

2010-05-25 Thread Henrique Andrade
Dear Riccardo, Kehl and Guilherme, I was looking for something simple. The option "loop for (n=6; n<=24; n*=2)" worked just fine. But in my humble opinion the option "loop for (n=6; n=12; n=24)" should work too, but this is not a big deal ;-) Thank you so much! Um abraço, Henrique Em 25 de maio

Re: [Gretl-users] Instumental variables

2010-05-25 Thread Sven Schreiber
Am 25.05.2010 17:02, schrieb Claudio Shikida (敷田治誠 クラウジオ): > Yes, but just as independent variables. I cannot include them as > instruments. That´s my question. Thanks for answering me, but the > problem persists for me. If you can use lags as instruments, so my > version has some bug. > which i

Re: [Gretl-users] Loop question

2010-05-25 Thread Henrique Andrade
Dear Riccardo, Kehl and Artur, Thanks a lot for your help! I'd tried all the options you gave me and my final script looks like this: scalar n=0 loop for (n=6;n<=24;n=n*2) --quiet scalar m = $T - n + 1 loop j=2..nelemY --quiet matrix R$n_$j = zeros(m,1) loop i=1..m --quie

Re: [Gretl-users] Instumental variables

2010-05-25 Thread Sven Schreiber
Am 25.05.2010 14:20, schrieb Claudio Shikida (敷田治誠 クラウジオ): > Hello to all, > > Straight to the point. I converted an old Eviews file to Gretl. The > series were ok, all was going well. They are time series. I updated the > series and generated the logs, d(logs) and also logs(-k) and dlogs(-k). > A

Re: [Gretl-users] Instumental variables

2010-05-25 Thread 敷田治誠 クラウジオ
Ah, I got it. My mistake. thanks. 2010/5/25 Claudio Shikida (敷田治誠 クラウジオ) > That´s weird. Mine is exactly this version, my windows is a 64 bits > (windows 7) and I still don´t get it. It seems obvious - even stupid - to me > that I should have this option. Maybe I have to reinstall it. > > Thank

Re: [Gretl-users] Instumental variables

2010-05-25 Thread 敷田治誠 クラウジオ
That´s weird. Mine is exactly this version, my windows is a 64 bits (windows 7) and I still don´t get it. It seems obvious - even stupid - to me that I should have this option. Maybe I have to reinstall it. Thank you so much. Claudio 2010/5/25 Sven Schreiber > Am 25.05.2010 17:02, schrieb Clau

Re: [Gretl-users] Instumental variables

2010-05-25 Thread 敷田治誠 クラウジオ
Yes, but just as independent variables. I cannot include them as instruments. That´s my question. Thanks for answering me, but the problem persists for me. If you can use lags as instruments, so my version has some bug. Claudio 2010/5/25 Sven Schreiber > Am 25.05.2010 14:20, schrieb Claudio Shi

Re: [Gretl-users] Loop question

2010-05-25 Thread Kehl D ániel
Or alternatively you can try loop i=1..n and use 6*i inside the loop if you need the numbers you wrote as an example. daniel -Original Message- From: "Riccardo (Jack) Lucchetti" To: Gretl list List-Post: gretl-users@gretlml.univpm.it Date: Tue, 25 May 2010 08:08:26 +0200 (CEST) Subjec

[Gretl-users] Instumental variables

2010-05-25 Thread 敷田治誠 クラウジオ
Hello to all, Straight to the point. I converted an old Eviews file to Gretl. The series were ok, all was going well. They are time series. I updated the series and generated the logs, d(logs) and also logs(-k) and dlogs(-k). All of this was fine. So I went to the Instrumental Variables in order t

Re: [Gretl-users] Loop question

2010-05-25 Thread Jack
On Tue, 25 May 2010, Henrique Andrade wrote: > Dear Gretl Community, > > I'm trying to use a loop index inside a script but I don't know how. According > to "Gretl User’s Guide" the syntax looks like this: > > loop i=1..24 > > But I just need the points where "i" is equal to 6, 12 and 24. Somet

[Gretl-users] Loop question

2010-05-25 Thread Henrique Andrade
Dear Gretl Community, I'm trying to use a loop index inside a script but I don't know how. According to "Gretl User’s Guide" the syntax looks like this: loop i=1..24 But I just need the points where "i" is equal to 6, 12 and 24. Something like this: loop i=6;12;24 How can I do that? Best rega