El 30/11/11 13:06, Giuseppe Vittucci escribió:
> Clearly, you can follow Jack's suggestion.
> In my suggestion, i.e.:
>
> loop foreach i 48 60 100 250 400 780
> ...
> endloop
>
> i is taken as a string.
> But you can always recall it inside the loop using $i:
> - defining a new scalar. E.g:
>
Clearly, you can follow Jack's suggestion.
In my suggestion, i.e.:
loop foreach i 48 60 100 250 400 780
...
endloop
i is taken as a string.
But you can always recall it inside the loop using $i:
- defining a new scalar. E.g:
loop foreach i 48 60 100 250 400 780
scalar j = $i
...
e
On Wed, 30 Nov 2011, Ignacio Diaz-Emparanza wrote:
> I need to build a loop with a not regulary spaced index, ¿what do you
> think it is the best way?
>
> I mean, for example a loop over i=48, 60, 100, 250, 400, 780
Something like this, perhaps?
x = {48, 60, 100, 250, 400, 780}
loop i=1..cols(
loop foreach i 48 60 100 250 400 780
...
endloop
Bye
Giuseppe
On Wed, 2011-11-30 at 11:21 +0100, Ignacio Diaz-Emparanza wrote:
> I need to build a loop with a not regulary spaced index, ¿what do you
> think it is the best way?
>
> I mean, for example a loop over i=48, 60, 100, 250, 400, 780
I need to build a loop with a not regulary spaced index, ¿what do you
think it is the best way?
I mean, for example a loop over i=48, 60, 100, 250, 400, 780
--
Ignacio Diaz-Emparanza
DEPARTAMENTO DE ECONOMÍA APLICADA III (ECONOMETRÍA Y ESTADÍSTICA)
UPV/EHU Avda. Lehendakari Aguirre, 83 | 48015
On Tue, 25 May 2010, Henrique Andrade wrote:
> Dear Riccardo, Kehl and Guilherme,
>
> I was looking for something simple. The option "loop for (n=6; n<=24;
> n*=2)" worked just fine. But in my humble opinion the option "loop for
> (n=6; n=12; n=24)" should work too, but this is not a big deal ;
On Tue, 25 May 2010, Henrique Andrade wrote:
> I was looking for something simple. The option "loop for (n=6;
> n<=24; n*=2)" worked just fine. But in my humble opinion the
> option "loop for (n=6; n=12; n=24)" should work too, but this is
> not a big deal ;-)
The three fields in the "classic" f
I disagree with your proposed syntax.
I should know that the current form of the loop for, comes from the C
language (and then C++ and Java).
I think that we could have something like:
loop n in 6 12 24 xlist
Where n is the loop variable 6, 12 and 24 are numbers, and xlist is a list
of the same t
On Tue, 25 May 2010, Henrique Andrade wrote:
> Now, because I just need the values for 6, 12 and 24, I'm trying to
> substitute the second line "loop for (n=6;n<=24;n=n*2)" for this:
>
> loop for (n=6;n=12;n=24)
>
> But the script isn't working. Any hints?
This, maybe?
scalar m = 3
scalar bas
.univpm.it
Date: Tue, 25 May 2010 16:53:54 -0300
Subject: Re: [Gretl-users] Loop question
Dear Riccardo, Kehl and Artur,
Thanks a lot for your help! I'd tried all the options you gave me and
my final script looks like this:
scalar n=0
loop for (n=6;n<=24;n=n*2) --quiet
scalar m = $T
Hi Henrique,
I believe that this does what you want:
loop for (n=6; n<=24; n*=2) --quiet
No other simple options.
On Tue, May 25, 2010 at 8:53 PM, Henrique Andrade wrote:
> Dear Riccardo, Kehl and Artur,
>
> Thanks a lot for your help! I'd tried all the options you gave me and
> my final scrip
Or, if your index is something like of a geometric series as it seems to
be (let's say 6, 12, 24, 48, and so on) and too long to do manually
you can try this one:
scalar count=0
loop for (count=6;count<=24;count=count*2) --quiet
endloop
<\script>
cheers,
artur
Riccardo (Jack)
Dear Riccardo, Kehl and Guilherme,
I was looking for something simple. The option "loop for (n=6; n<=24; n*=2)"
worked just fine. But in my humble opinion the option "loop for (n=6; n=12;
n=24)" should work too, but this is not a big deal ;-)
Thank you so much!
Um abraço,
Henrique
Em 25 de maio
Dear Riccardo, Kehl and Artur,
Thanks a lot for your help! I'd tried all the options you gave me and
my final script looks like this:
scalar n=0
loop for (n=6;n<=24;n=n*2) --quiet
scalar m = $T - n + 1
loop j=2..nelemY --quiet
matrix R$n_$j = zeros(m,1)
loop i=1..m --quie
0200 (CEST)
Subject: Re: [Gretl-users] Loop question
On Tue, 25 May 2010, Henrique Andrade wrote:
> Dear Gretl Community,
>
> I'm trying to use a loop index inside a script but I don't know how. According
> to "Gretl User’s Guide" the syntax looks like this:
>
> lo
On Tue, 25 May 2010, Henrique Andrade wrote:
> Dear Gretl Community,
>
> I'm trying to use a loop index inside a script but I don't know how. According
> to "Gretl User’s Guide" the syntax looks like this:
>
> loop i=1..24
>
> But I just need the points where "i" is equal to 6, 12 and 24. Somet
Dear Gretl Community,
I'm trying to use a loop index inside a script but I don't know how.
According
to "Gretl User’s Guide" the syntax looks like this:
loop i=1..24
But I just need the points where "i" is equal to 6, 12 and 24. Something
like this:
loop i=6;12;24
How can I do that?
Best rega
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