El 15/03/12 19:53, Anthony Cowley escribió:
On Thursday, March 15, 2012 at 2:27 PM, Juan Miguel Vilar wrote:
Hello, café:
I am trying to use more than one array with runSTUArray but I don't seem
to be able to understand how it works. My first try is this:
test1 n = runSTUArray $ do
a <- newArr
El 15/03/12 20:07, Daniel Fischer escribió:
On Thursday 15 March 2012, 19:53:56, Daniel Fischer wrote:
On Thursday 15 March 2012, 19:27:18, Juan Miguel Vilar wrote:
Hello, café:
However, when I write
test2 n = runSTUArray $ do
let createArray v n = newArray (1, n) (v::Int)
On Thursday 15 March 2012, 19:53:56, Daniel Fischer wrote:
> On Thursday 15 March 2012, 19:27:18, Juan Miguel Vilar wrote:
> > Hello, café:
>
> > However, when I write
> >
> > test2 n = runSTUArray $ do
> >
> > let createArray v n = newArray (1, n) (v::Int)
>
> Here you create a
On Thursday, March 15, 2012 at 2:27 PM, Juan Miguel Vilar wrote:
> Hello, café:
>
> I am trying to use more than one array with runSTUArray but I don't seem
> to be able to understand how it works. My first try is this:
>
> test1 n = runSTUArray $ do
> a <- newArray (1, n) (2::Int)
> b <- newAr
On Thursday 15 March 2012, 19:27:18, Juan Miguel Vilar wrote:
> Hello, café:
>
> I am trying to use more than one array with runSTUArray but I don't seem
> to be able to understand how it works. My first try is this:
>
> test1 n = runSTUArray $ do
> a <- newArray (1, n) (2::Int)
>
Hello, café:
I am trying to use more than one array with runSTUArray but I don't seem
to be able to understand how it works. My first try is this:
test1 n = runSTUArray $ do
a <- newArray (1, n) (2::Int)
b <- newArray (1, n) (3::Int)
forM_ [1..n] $ \i -> do
