Re: [JBoss-user] Access files in a war archive

2003-01-24 Thread Rod Macpherson
al Message - From: Stephen Ting To: [EMAIL PROTECTED] Sent: Friday, January 24, 2003 7:30 PM Subject: RE: [JBoss-user] Access files in a war archive How to create a exploded WAR? FYI, i used ANT to create the war archive and there is no JAR file included except in th

RE: [JBoss-user] Access files in a war archive

2003-01-24 Thread Stephen Ting
2003 01:59To: [EMAIL PROTECTED]Subject: RE: [JBoss-user] Access files in a war archive getRealPath works if the WAR is deployed as an exploded WAR (aka directory structure, no JAR file). -Original Message-From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]On Behalf

RE: [JBoss-user] Access files in a war archive

2003-01-24 Thread Bill Burke
]Subject: Re: [JBoss-user] Access files in a war archive There is no "real" path access from a war so the null return value is unfortunately correct: bin-there-dun-that. URL's will work but you will have to convert your file to an URL based on the session context:    

Re: [JBoss-user] Access files in a war archive

2003-01-24 Thread Rod Macpherson
iginal Message - From: Stephen Ting To: 'Jboss Mailing List' Sent: Thursday, January 23, 2003 10:32 PM Subject: [JBoss-user] Access files in a war archive Can anyone show me how access a xml file in .war archive through a relative path?

Re: [JBoss-user] Access files in a war archive

2003-01-23 Thread Steven Haines
Here is an example that gets a URL to the file "myxmlfile.xml" that is contained in the war's WEB-INF/xml directory: String xmlFile = getServletContext().getResource("/WEB-INF/xml/myxmlfile.xml").toString(); Depending on your XML library you might be able to open it directly passing this URL (JDO

[JBoss-user] Access files in a war archive

2003-01-23 Thread Stephen Ting
Title: Message Can anyone show me how access a xml file in .war archive through a relative path?   I try using the following codes but in vain. servlet.getServletContext().getRealPath(pathname) which return null; servlet.getServletContext().getResourceAsStream(pathname) also Thanks regard