modulus in JS returns the remainder of the division - whatever is left
that couldn't be divided returning an integer.
1/4 = 0.25 -> 1%4 = 1
2/4 = 0.5-> 2%4 = 2
3/4 == 0.75 -> 3%4 == 3
4/4 == 1 -> 4%4 == 0
5/4 == 1.25 -> 5%4 == 1
6/4 == 1.5-> 6%4 == 2
and so on...
By
Hi Ricardo,
Could you explain why you did %4 for the n variable?
On Feb 26, 12:16 pm, ricardobeat wrote:
> I like it cleaner:
>
> $('a').each(function(i){
> var n = Math.floor(i/10) % 4;
> $(this).addClass(
> n == 0 ? 'first' :
> n == 1 ? 'second' :
> n == 2 ? 'third' :
So do I :)
Using the modulus is best, and without a doubt fastest.
On Feb 26, 12:16 pm, ricardobeat wrote:
> I like it cleaner:
>
> $('a').each(function(i){
> var n = Math.floor(i/10) % 4;
> $(this).addClass(
> n == 0 ? 'first' :
> n == 1 ? 'second' :
> n == 2 ? 'third' :
I like it cleaner:
$('a').each(function(i){
var n = Math.floor(i/10) % 4;
$(this).addClass(
n == 0 ? 'first' :
n == 1 ? 'second' :
n == 2 ? 'third' :
n == 3 ? 'fourth' : '');
});
or
var classNames = ['first', 'second', 'third', 'fourth'];
$('a').each(function(i){
And just as an exercise, here's the 'jQuery' way chained:
$('a').filter(':lt(10)').addClass('first').end().filter(':gt(9):lt
(10)').addClass('second').end().filter(':gt(19):lt(10)').addClass
('third').end().filter(':gt(29)').addClass('fourth');
Not really any speed gain though.
On Feb 26, 1:21
It's possible. Here's a more traditional way:
$('a').each(function(i,link){
if(i<10){$(link).addClass('first');}
else if (i>9 && i<20){$(link).addClass('second');}
else if (i>19&&i<30){$(link).addClass('third');}
else if (i>29&&i<40){$(l
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