Try $('label').css('display'); this will return the value your looking
for.
On Oct 28, 7:39 am, [EMAIL PROTECTED]
[EMAIL PROTECTED] wrote:
Hi,
Given following, is there a way to get the value of 'display'? is it
'none' or something else?
thanks,
AC.
label for=state style=display:none;
Thanks, this works, I notice that css(display) will return block
when there is no style defined
On Oct 28, 7:13 pm, James Dempster [EMAIL PROTECTED] wrote:
Try $('label').css('display'); this will return the value your looking
for.
On Oct 28, 7:39 am, [EMAIL PROTECTED]
[EMAIL PROTECTED]
That's because .css('display') or any other css property returns the
computed style. As block is the default style for that element it will
return block on spans it will return inline as that's the default display
style.
/James
On 10/28/07, [EMAIL PROTECTED] [EMAIL PROTECTED] wrote:
Thanks,
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