Ah, thanks Karl, writing to this list has become one of my favorite
spare time hobbies :)
On Nov 13, 1:23 pm, Karl Swedberg <[EMAIL PROTECTED]> wrote:
> Not a problem, Ricardo. :-)
>
> sorry, everyone else, for going off-topic, but I'd like to thank
> Ricardo publicly for all the help he has be
Not a problem, Ricardo. :-)
sorry, everyone else, for going off-topic, but I'd like to thank
Ricardo publicly for all the help he has been giving to this list in
the past few months. Ricardo, your contributions are much appreciated.
Cheers,
--Karl
Karl Swedberg
www.englishrul
Oops. I always do that, write a non-functional draft in the reply body
and forget to correct it after testing! Thanks :D
On Nov 13, 2:21 am, Karl Swedberg <[EMAIL PROTECTED]> wrote:
> Actually, Ricardo's should work if ...
>
> 1. you change var $this = this; to var $this = $(this);
> 2. you know
On Nov 12, 2008, at 11:17 PM, Karl Swedberg wrote:
Hi Adam,
In that case, you'll probably need to use John Resig's nextUntil
plugin.
The way I managed to do it is a little sneaky. Someone else should
be able to come up with a better way. But in the meantime, you can
take a look at a wor
Beautiful! That edit worked with Ricardo's script. Thank you both very
much!
-Adam
On Nov 12, 9:21 pm, Karl Swedberg <[EMAIL PROTECTED]> wrote:
> Actually, Ricardo's should work if ...
>
> 1. you change var $this = this; to var $this = $(this);
> 2. you know for sure you'll only have two paragrap
Actually, Ricardo's should work if ...
1. you change var $this = this; to var $this = $(this);
2. you know for sure you'll only have two paragraphs after each h1
--Karl
Karl Swedberg
www.englishrules.com
www.learningjquery.com
On Nov 12, 2008, at 9:04 PM, Adam wrote:
Ricardo
Hi Adam,
In that case, you'll probably need to use John Resig's nextUntil plugin.
The way I managed to do it is a little sneaky. Someone else should be
able to come up with a better way. But in the meantime, you can take a
look at a working example here
Just view source for the script.
--
Ricardo,
Thanks for your response. Are you sure about this syntax? Ive tried
this and there's no result. The code is not modified at all...
-Adam
On Nov 12, 4:09 pm, ricardobeat <[EMAIL PROTECTED]> wrote:
> This should work for this specific case (separated in lines for
> readability):
>
> $('h1
This should work for this specific case (separated in lines for
readability):
$('h1').each(function(){
var $this = this;
$this
.add( $this.next() )
.add( $this.next().next() )
.wrapAll('');
});
- ricardo
On Nov 12, 7:48 pm, Adam <[EMAIL PROTECTED]> wrote:
> Karl,
>
Karl,
Thanks very much. My bad, but what I actually need is the div wrapped
around each of the sets of h1,p,p. So, the resulting code must be:
...
...
...
...
...
...
I have tried a number of different things, and this function works to
wrap the first set of 3 in the div:
$("#content h1:nt
Hi Adam,
Take a look at the .wrapAll() method. that should get you closer.
You'll need to select all of the elements first, though. $('h1 + p +
p') only selects that final p. If you want to wrap the div around all
h1 and p elements, you could try $('h1,p').wrapAll('class="fade">');
--Kar
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