Re: [julia-users] SymTridiagonal

2014-11-17 Thread Eka Palamadai
Semantically, ones(n,1) creates a vector and not a matrix. Why is ones(n,1) different from ones(n)? The type system is very confusing and non-intuitive. On Sunday, November 16, 2014 7:28:28 PM UTC-5, Andreas Noack wrote: The input should be two Vectors, but your first argument is a Matrix

Re: [julia-users] SymTridiagonal

2014-11-17 Thread Andreas Noack
Semantically, ones(n,1) creates a vector and not a matrix. I'd rather say that in MATLAB ones(n,1) creates a vector. This has been discussed many times on the list and in issues. In particular, see the famous https://github.com/JuliaLang/julia/issues/4774. In Julia, Vector{T} and Matrix{T}

Re: [julia-users] SymTridiagonal

2014-11-17 Thread Eka Palamadai
which I think is reasonable is a subjective argument. It would be helpful if the type system is intuitive and non-confusing to programmers. On Monday, November 17, 2014 12:24:58 PM UTC-5, Andreas Noack wrote: Semantically, ones(n,1) creates a vector and not a matrix. I'd rather say that in

Re: [julia-users] SymTridiagonal

2014-11-17 Thread Tim Holy
What's intuitive is very dependent upon your background. If you're coming from Matlab, for example, everything is a matrix and Matlab does this extraordinarily-confusing thing: ones(3,3,3) gives me a 3d array; ones(3,3) gives me a 2d array; but ones(3) ans = 1 1 1 1 1

Re: [julia-users] SymTridiagonal

2014-11-17 Thread Eka Palamadai
I don't know what matlab does. As a user, ones(n,1) and ones(n) both return me a vector, and it is confusing to find that ones(n,1) != ones(n). On Monday, November 17, 2014 12:53:25 PM UTC-5, Tim Holy wrote: What's intuitive is very dependent upon your background. If you're coming from

Re: [julia-users] SymTridiagonal

2014-11-17 Thread Tim Holy
Your best bet, then, is to decide as quickly as possible whether you want to use Julia. If you start reading here: http://docs.julialang.org/en/latest/manual/faq/#what-does-type-stable-mean you'll maximize your chances of quickly discovering other things that will likely annoy you :-). While

Re: [julia-users] SymTridiagonal

2014-11-17 Thread Douglas Bates
On Monday, November 17, 2014 12:02:07 PM UTC-6, Eka Palamadai wrote: I don't know what matlab does. As a user, ones(n,1) and ones(n) both return me a vector, and it is confusing to find that ones(n,1) != ones(n). As Andreas and Tim have tried to say, your claim that ones(n,1) and

Re: [julia-users] SymTridiagonal

2014-11-17 Thread Jeff Waller
As a user, ones(n,1) and ones(n) both return me a vector, and it is confusing to find that ones(n,1) != ones(n) I was where you are now a few months ago. It's a learning cure thing, I think, because now I don't make that mistake anymore or I'm like, oh yea, of course and change it 2

Re: [julia-users] SymTridiagonal

2014-11-17 Thread Eka Palamadai
Thanks. Fortunately (or unfortunately) i have to use julia, and will have to make noise where something is confusing. On Monday, November 17, 2014 1:26:09 PM UTC-5, Tim Holy wrote: Your best bet, then, is to decide as quickly as possible whether you want to use Julia. If you start reading

[julia-users] SymTridiagonal

2014-11-16 Thread Eka Palamadai
SymTridiagonal does not seem to work properly. For e.g, the following snippet fails. julia n=10 ; A=SymTridiagonal(2*ones(n,1), -1*ones(n-1)); ERROR: `convert` has no method matching convert(::Type{SymTridiagonal{T}}, ::Array{Float64,2}, ::Array{Float64,1}) in call at base.jl:34 Any

Re: [julia-users] SymTridiagonal

2014-11-16 Thread Andreas Noack
The input should be two Vectors, but your first argument is a Matrix 2014-11-16 19:25 GMT-05:00 Eka Palamadai ekanat...@gmail.com: SymTridiagonal does not seem to work properly. For e.g, the following snippet fails. julia n=10 ; A=SymTridiagonal(2*ones(n,1), -1*ones(n-1)); ERROR: