2013/7/5 John Kliewe :
> Hi,
>
> I am trying to create a measure like the attached, from Chopin's Nocturne
> #3.
[...]
> Any advice?
Use:
\mergeDifferentlyHeadedOn
Further explanations in the NR.
Cheers,
Harm
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Hi John,
\mergeDifferentlyHeadedOn is what you are looking for. The approach with
two voices was already right.
\version "2.16.0"
\new Staff \relative c' {
\clef bass
\time 6/8
\key b \major
\mergeDifferentlyHeadedOn
<< { cis,2 s4 } \\ { cis8[ e8 b' gis e' b] } >>
}
For more details,
Hi Pierre,
thanks again for your work.
I'll work on it the upcoming weekend.
2013/7/5 Pierre Perol-Schneider :
> 2013/7/5 David Kastrup
>>
>> I have my doubts. The exponential evaluates to
>> 0.13 * Staffsize ** (ln(0.13)/ln(20))
>
>
> Sorry for that, i'm trying to copy formulas from my excel f
Hi,
I am trying to create a measure like the attached, from Chopin's Nocturne #3.
Here is what I have tried, but neither approach is quite right :
\version "2.16.0"
upper=
\relative c''
{ \clef treble
\time 6/8
\key b \major
r2.
r2.
}
lower=
\relative c'
{ \clef bass
\time 6/8
\key b \m
2013/7/5 David Kastrup
> I have my doubts. The exponential evaluates to
> 0.13 * Staffsize ** (ln(0.13)/ln(20))
Sorry for that, i'm trying to copy formulas from my excel file and doing
mistakes (plus my wife's complaining...)
after few testings, it seems that 0.14 is a better aprox. figure so
Copy of some tests enclosed.
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Gentlemen,
Thanks for your replies.
Vaughan,
Your attachment was filtered out as a binary file by my email server.
The GNU.org archives also shows it as a .bin file so I cannot 'see'
what you've done. If you would, please attach it as a reply to this
email.
David, I think I understand what you
Pierre Perol-Schneider writes:
> 2013/7/5 Pierre Perol-Schneider
>
>>
>>
>> kern = x-length*10* EXP[ [ [LN(0.13)/LN(20)]*LN(StaffSize) ] - LN(0.13) ]
>>
>
> Sorry again, i'm righting too fast
> so last shot :
>
> kern = x-length*10* EXP[ [ [LN(0.13)/LN(20)]*LN(StaffSize) ] + LN(0.13) ]
>
> this
2013/7/5 Pierre Perol-Schneider
>
>
> kern = x-length*10* EXP[ [ [LN(0.13)/LN(20)]*LN(StaffSize) ] - LN(0.13) ]
>
Sorry again, i'm righting too fast
so last shot :
kern = x-length*10* EXP[ [ [LN(0.13)/LN(20)]*LN(StaffSize) ] + LN(0.13) ]
this one should be the good one...
I don't know that Urs was contemplating "irrational" in the mathematical
sense, but in the more logical sense of being something not governed by an
easily understood relationship, such as one measure generating two and the
next two generating one, and then maybe four develops to 10 and 9 to 5, or
s
2013/7/5 Pierre Perol-Schneider
>
> kern = x-length * EXP[ [ [LN(0.13)/LN(20)]*LN(StaffSize) ] - LN(0.13) ]
>
>
Sorry, I forgot one factor..
So here again "the" kern function :
kern = x-length*10* EXP[ [ [LN(0.13)/LN(20)]*LN(StaffSize) ] - LN(0.13) ]
2013/7/4 Thomas Morley
>
> So I should ask:
> How to get good results with different global-staff-size?
>
>
Hi Harm,
So here 's what I've found this evening :
kern = x-length * EXP[ [ [LN(0.13)/LN(20)]*LN(StaffSize) ] - LN(0.13) ]
Works pretty well from staff size = 15 to 30.
Did not test othe
Am 05.07.2013 17:20, schrieb David Kastrup:
Urs Liska writes:
Hi Richard,
thanks for your suggestions.
I was just thinking about how to deal with the different timings (I
would have found that too, but later) when your second suggestion came
in.
This works for the given situation.
But as you
Urs Liska writes:
> Hi Richard,
>
> thanks for your suggestions.
> I was just thinking about how to deal with the different timings (I
> would have found that too, but later) when your second suggestion came
> in.
>
> This works for the given situation.
> But as you say I will have situations whe
Hi Richard,
thanks for your suggestions.
I was just thinking about how to deal with the different timings (I
would have found that too, but later) when your second suggestion came in.
This works for the given situation.
But as you say I will have situations where it won't be sufficient
becaus
Hi Urs.
I tried to send a reply earlier. I don't know if I succeeded, but the method I
suggested was not good enough anyway. Here's my second attempt at a solution to
your problem:
\version "16.0"
firstVersion =\relative e'' {e2. e4 | g2. cis,4 |}
secondVersion =\scaleDurations #'(2 . 1)\relative
Hi Urs.
In your example, if you lay the second version out as if the notes had twice
the durations they actually have, then it looks nice:
\version "16.0"
firstVersion =\relative e'' {e2. e4 | g2. cis,4 |}
secondVersion =\scaleDurations #'(2 . 1)\relative e'' {e4~ e16[ fis] e[ fis]
g4. cis,8 |}
\
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