Re: Beam breaking

2020-08-01 Thread Urs Liska
Hi Andrew, sorry that I was confused by your example (which actually was *not* "minimal", with the excess information being actively misleading. The keyword "breakable" in combination with the explicit beams made me think you were after a broken beam, not also about the line break.) OK: You can o

Re: Beam breaking

2020-08-01 Thread Aaron Hill
On 2020-08-01 9:03 pm, Andrew Bernard wrote: Ah, is it to do with the tuplet not being breakable? Nope. It's because there was no barline to break at. Try: \bar "" \break Remember that your \tuplet 7/8 is scaling note durations. You could do this instead and see that you do not need to a

Re: Beam breaking

2020-08-01 Thread Andrew Bernard
Ah, is it to do with the tuplet not being breakable? On Sun, 2 Aug 2020 at 14:00, Andrew Bernard wrote: > > Sorry, but if you remove the explicit beam the same issue remains. I > am stumped. I am unable to understand your comment about 'at note > heads. Surely the break can only occur between not

Re: Beam breaking

2020-08-01 Thread Andrew Bernard
Sorry, but if you remove the explicit beam the same issue remains. I am stumped. I am unable to understand your comment about 'at note heads. Surely the break can only occur between notes? On Sun, 2 Aug 2020 at 13:37, Urs Liska wrote: > > Ah no, much simpler: If you ask LilyPond to print an expli

Re: Beam breaking

2020-08-01 Thread Urs Liska
Ah no, much simpler: If you ask LilyPond to print an explicit beam it will print an explicit beam ;-) Am Sonntag, den 02.08.2020, 05:35 +0200 schrieb Urs Liska: > Am Sonntag, den 02.08.2020, 13:32 +1000 schrieb Andrew Bernard: > > \version "2.21.4" > > > > > > > > { > > > > \time 7/8 > > >

Re: Beam breaking

2020-08-01 Thread Urs Liska
Am Sonntag, den 02.08.2020, 13:32 +1000 schrieb Andrew Bernard: > \version "2.21.4" > > > > { > > \time 7/8 > > \set Timing.measureLength = #(ly:make-moment 1/4) > > \override Beam.breakable = ##t > > \tuplet 7/8 { > > b'16[ b' b' b' > > \break > > c'' c'' c''] > >

Beam breaking

2020-08-01 Thread Andrew Bernard
Why won't this let me break the beam? Andrew % \version "2.21.4" { \time 7/8 \set Timing.measureLength = #(ly:make-moment 1/4) \override Beam.breakable = ##t \tuplet 7/8 { b'16[ b' b' b' \break c'' c'' c''] } | } %

Re: beam breaking with tuplets

2016-02-10 Thread Urs Liska
Hi Andrew, I can't compile your example on the mobile, but you are most certainly experiencing an issue where LilyPond doesn't behave according to its declared intention. (Assuming that with "broken" you mean subdivided). The proper handling of subdivisions under tuplets is on my agenda in rew

beam breaking with tuplets

2016-02-10 Thread N. Andrew Walsh
Hi List, I have the following expression: \version "2.19.36" \relative c'' { \set subdivideBeams = ##t \set baseMoment = #(ly:make-moment 1/8) \set beatStructure = #'(2 2 2 2) \time 4/8 \tuplet 3/2 { es,16\( f g } \tuplet 3/2 { a b cis\) } \tuplet 3/2 { dis\( eis g } a32 b16.->\) | }

Re: beam breaking in tuplets

2006-11-06 Thread Erik Sandberg
On Monday 06 November 2006 12:59, Mats Bengtsson wrote: > Erik Sandberg wrote: > > On Monday 06 November 2006 09:25, Mats Bengtsson wrote: > > > > Mats, do you think it would be useful with an operator \newClone to clone > > the current context? E.g. > > \new Staff \with {\consists Foo_engraver bar

Re: beam breaking in tuplets

2006-11-06 Thread Mats Bengtsson
Erik Sandberg wrote: On Monday 06 November 2006 09:25, Mats Bengtsson wrote: Victor Eijkhout wrote: So, if you want a limited scope, you can explicitly create a short-lived context. Here's an example that uses smaller note heads for one measure: \relative c'{ c d e f \new Voice {\tiny g f

Re: beam breaking in tuplets

2006-11-06 Thread Erik Sandberg
On Monday 06 November 2006 09:25, Mats Bengtsson wrote: > Victor Eijkhout wrote: > So, if you want a limited scope, you can explicitly create a short-lived > context. > Here's an example that uses smaller note heads for one measure: > > \relative c'{ c d e f \new Voice {\tiny g f e d } c d e d c1 }

Re: beam breaking in tuplets

2006-11-06 Thread Mats Bengtsson
Victor Eijkhout wrote: Beam breaking is a visual operation, not a mathematical one. I want a sixteenth beam broken at any beat boundary, no matter whether this is in 4/4 time or in a 27 over 26 fragment. I don't agree completely. Beam breaking is used to clarify the rhythmic stru

Re: beam breaking in tuplets

2006-11-05 Thread Victor Eijkhout
bes } | r4 g8 a16 bes a16 bes c8 | } \version "2.9.27" Bad side effects. But I think this approach points to a design error. Beam breaking is a visual operation, not a mathematical one. I want a sixteenth beam broken at any beat boundary, no matter whether this is in 4/4 time o

Re: beam breaking in tuplets

2006-11-05 Thread Mats Bengtsson
If you divide a 3/4 measure into 4 equal beats, then each beat will be 3/16 long. So, you can obtain what you want with #(override-auto-beam-setting '(end * * * *) 3 16) #(override-auto-beam-setting '(end * * * *) 6 16) #(override-auto-beam-setting '(end * * * *) 9 16) Since this is a fairly un

beam breaking in tuplets

2006-11-05 Thread Victor Eijkhout
Is this a bug or a feature? (2.9.27, PPC) \relative c'' { \time 3/4 \times 3/4 { r4 g8 a16 bes a8 bes16 c d8 c16 bes } | #(override-auto-beam-setting '(end 1 16 * *) 2 4) r4 g8 a16 bes a8 bes16 c | } I was expecting the beam in the tuplet to be broken the same way as in the measure after. I

beam-breaking at time sig

2003-09-21 Thread Peter Lutek
wondering if there's a way to break a beam at a barline which has a time sig change, so the beam doesn't clash with the time sig. i still want the visual sense of beaming over the barline, so want to end up with "hanging" partial beams on either side, just like when you break a beam over a line

Re: beam breaking

2003-06-04 Thread Graham Percival
On Tue, 03 Jun 2003 14:33:35 + David Bobroff <[EMAIL PROTECTED]> wrote: > In the following example I want to reduce the beams between the first > and second notes. According to the docs: > > \property Voice.subdivideBeams = ##t > > ..is what I need to use. It is having no effect. What am I

Re: beam breaking

2003-06-04 Thread Rune Zedeler
David Bobroff wrote: In the following example I want to reduce the beams between the first and second notes. According to the docs: \property Voice.subdivideBeams = ##t ..is what I need to use. It is having no effect. What am I doing wrong? The docs say tgat subdivideBeams subdivides the beams

beam breaking

2003-06-04 Thread David Bobroff
In the following example I want to reduce the beams between the first and second notes. According to the docs: \property Voice.subdivideBeams = ##t ..is what I need to use. It is having no effect. What am I doing wrong? -David Bobroff Lilypond 1.7.20 \score { \notes \relative c, {