Title: FileOpenDialog problem
Greetings List,
Does anyone have any idea what could be causing the following problem
When executing the following line of code a dialog with the error message Unable to access string resource (3395) appears
FileName = FileOpenDlg(D:\testfiles,,*.csv,Select
Very interesting... Even when I tried it with:
FileName = FileOpenDlg(D:\testfiles,*.csv,csv,Select CSV File)
I also got the error (using MI 7.8). But even more interesting, when I
tried:
FileName = FileOpenDlg(D:\testfiles,*.ick,ICK,Select ICK File)
there was no error. (And I'm pretty sure
